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Sum of coeff. |
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| Mar19-07, 01:11 PM | #1 |
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Sum of coeff.
1. The problem statement, all variables and given/known data
Evaluate: [tex]^{30}C_0 ^{30}C_{10}-^{30}C1 ^{30}C_11+...+^{30}C_{20} ^{30}C_{30}[/tex] Again, I know this is some coeff of the product of some series, but I dont know how to find the series or the coeff. I dont know how to go about it. |
| Mar19-07, 04:39 PM | #2 |
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To evaluate it, wouldn't you actually need to know what the [itex]C_i[/itex] actually are? Because if they're unknown constants, then I have no idea what is meant by evaluating that. Plus, your equation is not totally clear. You have a negative randomly put it where all the others are positives. You should explicitly write when the negatives are to be. |
| Mar19-07, 06:41 PM | #3 |
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Would those be the binomial coefficients? If so your nCi is more commonly written nCi.
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| Mar19-07, 09:29 PM | #4 |
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Sum of coeff.
is the thing alternating or what?
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| Mar20-07, 11:12 AM | #5 |
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I'm assuming the thing is alternating..
Try working out the first few terms... Alternately, try to write a formula for the nth term, and a formula for the (n+1)th term. See what happens when you add them together. |
| Mar20-07, 01:47 PM | #6 |
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Yes, those are binomial coefficients. The general term comes out to be
[tex](-1)^n^{30}C_r ^{30}C_{10+r}[/tex] where r varies from 0 to 20. |
| Mar20-07, 07:11 PM | #7 |
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hint:
1.[tex]\binom{a}{b}=\binom{a}{b-a}[/tex] 2. look at [tex](1-x)^n(1+x)^n[/tex] in general, when you have two series [tex]S_1=\sum_n a_n x^n[/tex] [tex]S_2=\sum_n b_n x^n[/tex] [tex]S_1S_2=\sum_n\sum_{i+j=n} a_i b_jx^n[/tex] |
| Mar21-07, 01:36 AM | #8 |
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Can someone work the first two steps or something and I can try to work the rest out?
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| Mar23-07, 04:42 PM | #9 |
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reformulate the problem, basically you are asked to find,
[tex]\sum_{i=0}^{20} (-1)^n\binom{30}{i}\binom{30}{20-i}[/tex] look at the function [tex]f(x)=\sum_{n}\left [\sum_{i=0}^{20} (-1)^n\binom{30}{i}\binom{30}{20-i}\right ]x^n[/tex] from the equation I posted last time [tex]S_1S_2=\sum_n\sum_{i+j=n}a_ib_jx^n=\sum_n\sum_{i=0}a_ib_{n-i}x^n[/tex] what can you conclude? what [itex]S_1[/itex] and [itex]S_2[/itex] should you construct to finish the problem? |
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