Finding the Height of a Triangle Using Related Rates

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SUMMARY

The discussion focuses on calculating the height of a triangle using related rates, given two sides increasing at 0.5 feet per second and an included angle decreasing at 2 degrees per second. The specific scenario involves sides measuring 5 feet and 8 feet, with an included angle of 60 degrees. The area of the triangle can be expressed using the formula Area = (1/2) * base * height, where the height is derived from the right triangle formed by dropping a perpendicular from one side to the base. The use of vector cross products is suggested for a more efficient area calculation.

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franz32
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Hello here's the problem:

Each of the two sides of a triangle are increasing at the rate of 1/2 foot per second, and the included angle is decreasing 2 degrees per second. Find the rate of change of the area when the sides and included angle are respectively 5ft., 8ft., and 60 deg.

Here is my question: How do I find the height of the triangle?
Say my base is 5ft. How do I express it in terms of the given details in the problem?
 
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Try finding a better formula for the area of a triangle involving the two given sides and the included angle. (Think vector cross products, perhaps.)
 
Area= (1/2) height times base where the "height" is measured perpendicular to the "base". Take one of the given sides as base, and drop a perpendicular to it. The other given side is the hypotenuse of the right triangle formed. The height you need is the "opposite side" of that right triangle.
 

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