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Equal area question |
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| Apr1-07, 08:57 PM | #1 |
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Equal area question
1. The problem statement, all variables and given/known data
"Find a horizontal line y=k that divides the area between y=x^2 and y=9 into two parts" 2. Relevant equations 3. The attempt at a solution Found intersection at (-3,9), (3,9) Found total area to be 36, half(the area needed for each portion) to be 18. Don't know where to go from here. |
| Apr1-07, 09:33 PM | #2 |
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Find the two areas as a function of k.
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| Apr1-07, 11:09 PM | #3 |
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| Apr1-07, 11:15 PM | #4 |
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Equal area question
y=k divides the total area into two parts, A1=A1(k) and A2=A2(k). You need to find an expression for each area as a function of k and then find the value of k for which A1(k)=A2(k)
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| Apr1-07, 11:19 PM | #5 |
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Don't be intimidated by the variable k -- the fact it's there changes nothing. You know how to compute areas, so compute the area of one of the portions.
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| Apr2-07, 06:13 AM | #6 |
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What is the area of the region bounded by y= k, y= 9 and y= x2? For what value of k is that 18?
Even simpler: What is the area of the region bounded by y= 0, y= k and y= x2? For what value of k is that 18? |
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