maximum and minimum value question


by afcwestwarrior
Tags: maximum, minimum
afcwestwarrior
afcwestwarrior is offline
#1
Apr2-07, 09:38 PM
P: 457
what does this mean , my question says sketch the graph of a function who has a local maximum at 2 and is differentiable at 2,

what does it mean by it is differentiable at 2,
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afcwestwarrior
afcwestwarrior is offline
#2
Apr2-07, 09:47 PM
P: 457
does this mean that the slope is 0 at 2
afcwestwarrior
afcwestwarrior is offline
#3
Apr2-07, 09:53 PM
P: 457
well if u need to know what this means, it means if it is differentiable at 2 it is continous at 2

afcwestwarrior
afcwestwarrior is offline
#4
Apr2-07, 10:02 PM
P: 457

maximum and minimum value question


one more thing how do i sketch this graph, all it gives me is it is continous at 2, does it matter how i sketch this graph, does it have to be a certain type, does it have to look a certain way, in the back of my book it is a parabola and its continous on the negative side
baolkvn
baolkvn is offline
#5
Apr2-07, 10:20 PM
P: 4
Well, differentiable and continous is not equivalent. continous if differentiable, but if continous, we can't conlude it is differentiable.
2 formulas below are definition of continous and differentiable properties of a funtion, for example,F(x) :
+ F(x) is continous at x0 <=> limit of F(x) when x->x0 is equal to F(x0)
+ F(x) is differentiable at x0 <=> limit of [F(x)-F(x0)]/[x-x0] when x->x0 exists (that value is so called F'(x0) )
Anyway, note that : "differentiable" and "continous" is not equivalent. "continous" if differentiable, but if "continous", we can't conlude it is differentiable.
If you have anymore question, feel confidently to ask me.
Mystic998
Mystic998 is offline
#6
Apr3-07, 12:14 AM
P: 206
Well, strictly speaking, it doesn't have to look particularly normal to satisfy the requirements. But likely for your purposes, you're going to want something that's continuous in an interval around 2 and appears "smooth" at 2 (i.e., it has no sharp edge).
Gib Z
Gib Z is offline
#7
Apr3-07, 02:49 AM
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P: 3,353
Quote Quote by afcwestwarrior View Post
does this mean that the slope is 0 at 2
Yes. It also means it is continuous at 2. Seeing as they had a parabola, it seems this function is one where the domain is limited.


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