How Do You Calculate the Distance Between Two Points in a Folded Rectangle?

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SUMMARY

The discussion focuses on calculating the distance between two points A and B in a folded rectangle, specifically when the rectangle is folded along its diagonal. The formula proposed for the distance is d = √(a² + b² - (2a²b²)/(a² + b²)), which simplifies to d = √((a⁴ + b⁴)/(a² + b²)). The user confirms the accuracy of this formula, having derived it using Pythagorean theorem and the cosine law. The conversation also touches on the potential for alternative methods to achieve the same result.

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  • Understanding of Pythagorean theorem
  • Familiarity with the cosine law
  • Basic knowledge of geometry involving rectangles
  • Concept of folding geometric shapes
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  • Explore the cosine law in three-dimensional geometry
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Chen
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Ok, you take a rectangular and fold it along one of its diagonal, so that the two planes are perpendicular to each other.

Using [tex]a[/tex] and [tex]b[/tex], what is the distance between the points A and B ([tex]d[/tex])?

My anwer is:
[tex]d = \sqrt{a^2 + b^2 - \frac{2a^2b^2}{a^2 + b^2}} = \sqrt{\frac{a^4 + b^4}{a^2 + b^2}}[/tex]
But I doubt that it's actually correct. :)
 

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By the way, this is how I solved it (see attachment). I found x and f with Pythagoras, and using f I found y with the cosine law (the extended Pythagoras thing :wink:). And from there I just used x and y to find d with Pythagoras.

So is this correct, and is there an easier way to do this?
 

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I got the same answer so I am sure it is correct. The only slight difference in what I did was I used the two perpendicular heights and the distance between them.
 

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