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Calculation Help Needed... |
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| Apr7-07, 07:45 AM | #1 |
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Calculation Help Needed...
1. The problem statement, all variables and given/known data
Find the mass: ![]() 2. Relevant equations Not Sure. 3. The attempt at a solution I don't know where to start as I believe that there is less information. All that I have got upto is Tan-1(3/8) but I don't know if this is needed to find the mass?
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| Apr7-07, 07:48 AM | #2 |
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I'm assuming the frame is massless, pivoted bout the right angle of the triangle and the system is in equilibrium, am I correct?
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| Apr7-07, 08:51 AM | #3 |
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| Apr7-07, 08:57 AM | #4 |
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Calculation Help Needed...
So, we know that since the system is in equilibrium, the sum of the moments about any point should be zero. However, lets consider the forces; if the system is not translating (i.e. moving up or down) what must be the vector sum of the vertical forces?
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| Apr7-07, 08:59 AM | #5 |
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| Apr7-07, 09:06 AM | #6 |
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Sounds good to me
and where will this reation force be applied?
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| Apr7-07, 09:12 AM | #7 |
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| Apr7-07, 09:18 AM | #8 |
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Normal forces are applied at the point where the system pivots. Just checking, is the side x attached to a wall of some kind?
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| Apr7-07, 09:21 AM | #9 |
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x and y dimensions are given if to calculate the angle (I think). |
| Apr7-07, 09:31 AM | #10 |
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Okay, let us consider the torques about the pivot point;
[tex]0.08T\sin\left(\arctan\left(\frac{3}{8}\right)\right) = 0.4mg[/tex] Where T is the tension in the diagonal member. Do you follow? |
| Apr7-07, 09:38 AM | #11 |
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| Apr7-07, 09:56 AM | #12 |
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| Apr7-07, 02:50 PM | #13 |
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You still have not set up the equalibrium of FORCES, only of torques..
Also, for your information, [tex]\sin(\arctan(x))=\frac{x}{\sqrt{1+x^{2}}}[/tex] |
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