How Does Compound Interest Affect Birthday Savings Over 20 Years?

  • Thread starter Thread starter Johnny Leong
  • Start date Start date
  • Tags Tags
    Geometric
Click For Summary

Homework Help Overview

The discussion revolves around a problem involving compound interest and savings over a period of 20 years, specifically focusing on the total value of savings on a son's twenty-first birthday after depositing $10 each year on his birthdays at a 3% interest rate.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants explore different interpretations of the problem, including the timing of interest accumulation and the correct formula for calculating the total value of the savings. There are attempts to clarify the series involved and the implications of the deposits made each year.

Discussion Status

Multiple interpretations of the problem are being explored, with some participants questioning the assumptions about how interest is applied and the correct formula to use. There is no explicit consensus on the correct approach, but various lines of reasoning are being discussed.

Contextual Notes

Participants are considering the implications of the deposits made each year and how they affect the total value at the end of the 20-year period. There is uncertainty regarding the application of the geometric series formula and whether the last deposit affects the total value on the twenty-first birthday.

Johnny Leong
Messages
48
Reaction score
0
Question:
A man puts $10 in the bank for his son on each of his birthdays from the first to the twentieth inclusive. If the money accumlates at 3% compound interest, what is the toatl value on the son's twenty-first birthday?

My answer is like this:
a = 10, r = 1.03, n = 20
Total value = a * (r^n - 1) / (r - 1) = 10 * (1.03^20 - 1) / 0.03 = 269 (approx.)

But the answer is 276, what is the problem?
The $10 of the first year will immediately be counted for interest or not? And also how to define the final year, it is the 20th year or the 21st year?
 
Physics news on Phys.org
Hmmmmm

I just did it in a spreadsheet, and I got $286.76, which doesn't match either answer.

I used Microsoft Works, so I am prepared to blame Bill Gates if my answer is wrong.

Aha! Maybe he doesn't put $10 in on the 21st birthday, so subtract $10.00 from $286.76, and you get $276.76. Yeah, I think that's what is going on. That last year the account grows, but no new principle is put into the account.
 
Last edited:
Janitor, the original problem said "A man puts $10 in the bank for his son on each of his birthdays from the first to the twentieth inclusive" so there is no "maybe" about it.

Johnny Leong, you have the formula wrong. The sum of the geometric series [tex]\Sigma_{i=0}^n{ar^i}[/tex] is [tex]a\frac{1-r^{n+1}}{1-r}[/tex], not [tex]a\frac{1-r^n}{1-r}[/tex].
 
Last edited by a moderator:
Is it just me or are you all missing something?

If the "man puts $10 in the bank for his son on each of his birthdays", then the series should be defined like this:

[tex]a_0 = 0[/tex]
[tex]a_{n+1} = a_n 1.03 + 10[/tex]

And if that is the case, the series is no longer purely geometric so the formula above cannot be used to calculate the sum.
 
Chen, that means on the son's first birthday. He has $10 and on his 21st birthday, he will be having a21 = 1.03 * a20, don't have another $10 added.
The expanded form of a21 = 1.03 * (10 + 1.03 * 10 + 1.03^2 * 10 + ... + 1.03^19 * 10) = 10 * (1.03^21 - 1) / (1.03 - 1) - 10 = 276.
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
2K
Replies
2
Views
11K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
3
Views
5K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
Replies
2
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
7
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K