## Tension on ropes

1. The problem statement, all variables and given/known data
A 1100 kg steel beam is supported by two ropes. Each rope has a maximum sustained tension of 6200 N.

Then it shows a diagram of two ropes holding a steal beam at the center, both are angled out. The rope on the left is angled away at 20 deg from y axis. The rope on the right is angled 30 deg from y axis.

2. Relevant equations
Fnet = ma

3. The attempt at a solution
So basically I used substitution...
R1 = rope 1 (left)
R2 = rope 2 (right)
E = summation
F = Force

E(Fx) = MAx = 0

R2*sin(30) - R1*sin(20) = 0
R2*sin(30) = R1*sin(20)
R2 = R1*[sin(20)/sin(30)]

Plug that into sum of forces in y direction...

E(Fy) = MAy = 0

R1*cos(20) + R2*cos(30) - Mg = 0
R1*cos(20) + R2*cos(30) = Mg = 10791 N
plug in R2...
R1*[cos(20) + sin(20)/sin(30)] = 10791
R1 = 6645.96 N

Now I did it like this.. plugged that back into the original and got 4546.11 N for R2. However it was wrong. So I thought okay since the max tension is supposedly 6200 I'll use that as R1 and got 4241.05 for R2. Wrong again. Any ideas?
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 Quote by spin360 R1*cos(20) + R2*cos(30) - Mg = 0 R1*cos(20) + R2*cos(30) = Mg = 10791 N plug in R2... R1*[cos(20) + sin(20)/sin(30)] = 10791 R1 = 6645.96 N
Redo your plugging in of R2; looks like you dropped the cos(30).

 Quote by Doc Al Redo your plugging in of R2; looks like you dropped the cos(30).
Not sure where you're getting the cos... both are sine since the x vector is opposite of the angle.. making it sine. Right?

## Tension on ropes

here is the problem

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The cosine you dropped is the one right here:
 Quote by spin360 R1*cos(20) + R2*cos(30) - Mg = 0 R1*cos(20) + R2*cos(30) = Mg = 10791 N
 oh wow what a stupid mistake, thanks! it works now

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