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Springs in series and parallel : Problem for U |
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| Apr21-07, 07:12 AM | #1 |
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Springs in series and parallel : Problem for U
I came across an objective question on the topic 'Springs in series and parallel' .. Have i asnwered it correctly?
Q. A Force of 5Kg compresses 2 springs in series by 10 cm. What will be the compression when the same force acts on the same 2 springs but when the springs are in parallel? Choices >> 1) 5 cm 2) 10 cm 3) 2.5 cm 4) 20 cm MY ANSWER >> 2.5 cm Please correct me if I am wrong.. |
| Apr21-07, 09:31 AM | #2 |
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You are correct !
though it should have been mentioned that the springs are identical but as nothing is mentioned we can take them to be identical |
| Apr21-07, 11:54 PM | #3 |
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Thanks buddy...
Oh yes, U r spot on.. I forgot to mention that the springs are identical.. The logic I followed was >> In series, * The compression is 10 cm * This means each spring compresses by 5cm * Since the springs are in series, both the springs experience the full 5 kg force * So, each spring compresses 1 cm for 1 kg (Spring constant=1) In parallel, * Now, the force is divided between the 2 springs * So, force acting on each spring is 2.5 N * So, in this case, the spring compresses to 2.5xSpring constant(1) = 2.5 cm Hope I am right with my logic too.. Sorry, I should have mentioned this earlier
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| Apr22-07, 09:53 AM | #4 |
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Springs in series and parallel : Problem for U
most welcome
well....your logic seems correct but some problem in units. u say spring constant is 1?? if its 1 it must be 1 cm/kg wt but in si it will be not be so but later you say the force on each spring is 2.5 N it can't be its 2.5kg wt otherwise your soln is correct n btw ... if you are preparing for some objective type examinatiom then you can use for series 1/k=1/k1+1/k2 and parallel k=k1+k2 where k is equivalent spring constant |
| Apr23-07, 12:12 AM | #5 |
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Thanx chap..
(Ooops, the 2nd force that I mentioned is 2.5 KG (Not Newton) ... by mistake I wrote it as 2.5N) |
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