Population Allele Frequency and Heterozygotes in H-W Equilibrium

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SUMMARY

The discussion focuses on calculating the heterozygote frequency in a population with two alleles, B and b, under Hardy-Weinberg equilibrium. Given that the allele frequency of B (p) is 0.73, the frequency of allele b (q) is determined to be 0.27. The heterozygote frequency, represented by the term 2pq, can be calculated using the established Hardy-Weinberg equations: p + q = 1 and p² + 2pq + q² = 1.

PREREQUISITES
  • Understanding of Hardy-Weinberg equilibrium principles
  • Knowledge of allele frequency calculations
  • Familiarity with basic population genetics
  • Ability to manipulate algebraic equations
NEXT STEPS
  • Study the implications of Hardy-Weinberg equilibrium in real-world populations
  • Learn how to apply Hardy-Weinberg equations to different genetic scenarios
  • Explore factors that can disrupt Hardy-Weinberg equilibrium
  • Investigate the significance of heterozygosity in population genetics
USEFUL FOR

Genetics students, population biologists, and researchers interested in understanding allele frequencies and genetic variation in populations.

komal12
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A population has two alleles, B and b. the allele frequency of B is 0.73. what is the heterozygotes frequency, if the population is in H-W equilibrium?
 
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How about writing the appropriate equation for HARDY-WEINBERG equilibrium.

Look at

http://users.rcn.com/jkimball.ma.ultranet/BiologyPages/H/Hardy_Weinberg.html
 
two major important equations for Hardy-Weinberg:
p + q = 1
and p^2 + 2pq + q^2 = 1

You know 'p' in your problem: it is .73 Therefore you must know that 'q' is .27
since you know p = .73 and q = .27 you can find 2pq (which is the heterozygote frequency)
{Moderator edit: remainder of solution deleted. The student can solve from here on their own.}[/color]
 
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