Butis really so easy? (Möbius inversion)

[tpm]

But..is really so easy? (Möbius inversion), let be F(x) and G(x) functions

F(x)= G(ax)+G(2ax)+G(3ax)+...

for n=,1,2,3,4,5,... a is a fixed real number. then

G(ax)= \sum_{n=1}^{\infty}\mu (x) F(nx)

is seems too easy for me, to be true.

 

[matt grime]

Why don't you try it? (You might want to make sure you state it properly.)