But..is really so easy? (Möbius inversion)

*tpm*

But..is really so easy? (Möbius inversion), let be F(x) and G(x) functions

[tex] F(x)= G(ax)+G(2ax)+G(3ax)+............... [/tex]

for n=,1,2,3,4,5,............ a is a fixed real number. then

[tex] G(ax)= \sum_{n=1}^{\infty}\mu (x) F(nx) [/tex]

is seems too easy for me, to be true.

matt grime

Why don't you try it? (You might want to make sure you state it properly.)

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tpm	But..is really so easy? (Möbius inversion) Tweet But..is really so easy? (Möbius inversion), let be F(x) and G(x) functions [tex] F(x)= G(ax)+G(2ax)+G(3ax)+............... [/tex] for n=,1,2,3,4,5,............ a is a fixed real number. then [tex] G(ax)= \sum_{n=1}^{\infty}\mu (x) F(nx) [/tex] is seems too easy for me, to be true.

matt grime Recognitions: Homework Help Science Advisor	Why don't you try it? (You might want to make sure you state it properly.)