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a coil of wire is connected to an uncharged capacitor in a magnetic field....

 
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Jun7-07, 10:29 PM   #1
 

a coil of wire is connected to an uncharged capacitor in a magnetic field....


1. The problem statement, all variables and given/known data
A 10-turn coil of wire having a diameter of 1.0 cm and a resistance of 0.20 ohms is in a 1.0 mT magnetic field
with the coil oriented for maximum flux. The coil is connected to an uncharged 1.0 microFarad capacitor rather than to a current meter. The coil is quickly pulled out of the magnetic field. Afterward, what is the voltage across the capacitor?
Hint: Use I=dq/dt to relate the net change of flux to the amount of charge that flows to the capacitor.


2. Relevant equations
potential difference = -L dI/dt, where L is the inductance
magnetic field, B = Uo NI/l
total magnetic flux = N (magnetic field for each turn) = N (Area)(B) = (Uo N^2 A I) / l
I = V/R
induced emf = |change in magnetic flux/change in time|
V = Q/C

3. The attempt at a solution
Voltage across the capacitor initially is 0 V, since capacitor is uncharged.
I found the total flux to be 7.85 x 10^-7 Wb.
The changing flux induces an emf.

I'm really stuck here. Can someone please help me? Thanks :)
 
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Jun8-07, 12:22 AM   #2
 
Quote by ANON View Post
1. The problem statement, all variables and given/known data
A 10-turn coil of wire having a diameter of 1.0 cm and a resistance of 0.20 ohms is in a 1.0 mT magnetic field
with the coil oriented for maximum flux. The coil is connected to an uncharged 1.0 microFarad capacitor rather than to a current meter. The coil is quickly pulled out of the magnetic field. Afterward, what is the voltage across the capacitor?
Hint: Use I=dq/dt to relate the net change of flux to the amount of charge that flows to the capacitor.


2. Relevant equations
potential difference = -L dI/dt, where L is the inductance
magnetic field, B = Uo NI/l
total magnetic flux = N (magnetic field for each turn) = N (Area)(B) = (Uo N^2 A I) / l
I = V/R
induced emf = |change in magnetic flux/change in time|
V = Q/C

3. The attempt at a solution
Voltage across the capacitor initially is 0 V, since capacitor is uncharged.
I found the total flux to be 7.85 x 10^-7 Wb.
The changing flux induces an emf.

I'm really stuck here. Can someone please help me? Thanks :)
no time is given? if you're given a time then you have [tex]\frac{d\phi _B}{dt}[/tex] and a voltage
 
Jun8-07, 05:23 AM   #3
 
No time is given.
 
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