How Do I Solve a Quadratic Regression for a Helicopter Jump Trajectory?

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Discussion Overview

The discussion revolves around solving a quadratic regression problem related to a helicopter jump trajectory. Participants are exploring how to model the jump mathematically, considering the effects of gravity and initial conditions, while addressing the specific parameters given in the problem.

Discussion Character

  • Exploratory
  • Mathematical reasoning
  • Homework-related

Main Points Raised

  • One participant describes the scenario involving a helicopter 2500 ft from a target, with specific heights and speeds, and expresses difficulty in applying the quadratic formula to determine the jump timing and impact speed.
  • Another participant challenges the value of gravitational acceleration used, suggesting that it should be -32.19 ft/s² instead of -16 ft/s².
  • A participant mentions using the falling body formula and notes confusion regarding the initial vertical velocity, indicating that the helicopter's horizontal motion complicates the trajectory calculation.
  • One participant asserts that the initial vertical velocity is zero, as the helicopter is only moving horizontally, which may affect the calculations being made.

Areas of Agreement / Disagreement

Participants express differing views on the appropriate value for gravitational acceleration and the implications of the helicopter's horizontal motion on the initial vertical velocity. The discussion remains unresolved, with no consensus on the correct approach to the problem.

Contextual Notes

There are limitations regarding the assumptions made about the initial conditions, particularly the treatment of horizontal speed and its effect on the vertical trajectory. The mathematical steps taken by participants are not fully resolved, leading to uncertainty in the calculations.

curiousguy
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I have been trying to figure this out for 2 weeks.
A helicopter is begins its horizontal motion 2500 ft from the center of a targe 30 ft above the target traveling at 40mph. The target ( a pile of boxes) is stacked 15 ft high off the ground. At the appropriate time, a person is to jump out of the helicopter and hit the target. For the purpose of this problem, my professor says do not consider the horizontal speed of the jumper. I am to find the quad formula and parabola that states 1) when the person should jump to hit the target, 2) the speed of the jumper upon impact with the target. HELP! I am soooo stuck. I cannot get the quad formula for this! I did convert mph to ft per sec. Is it rational to use 16 ftpersec^2 as "g", acceleration due to gravity? When I use it, and graph the parabola it doesn't come close to hitting the target. When I try to graph the parabola from a couple of coordinates I know, it won't do it. HELP!
 
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Why can't everyone just use the metric system?
Your first problem is that g is not -16ft/s^2 but more like
-32.19ft/s^2... try that
 
The professor has us using the falling body formula=- 1/2 32ft/s^2 + Init.Velocity + Init. Height(y intercept) That's why the -16 is there. I have narrowed down the problem I am having... its the initial velocity. Since I have been instructed to not take into account the horizontal movement of 40mph (of 58.57 ft/sec), then the parabola I come out with makes NO sense. It traces the maximum of the parabola to approx 90 ft, meaning when the guy jumps out of the helicopter, he first climbs up to 90 ft in the air, before gravity takes over and pulls him back down. Well, I know that's not right. I have spending the past 2 wks throwing stuff and jumping off of stuff just to figure out this problem! Oh, if only my grade weren't so important to me. But it is. Do you know what I am supposed to do about initial velocity? If I try to put in "0"x, it comes out to no solution. Arg. Thank you for the suggestion.. keep them coming.
 
The initial vertical velocity is zero since the helicopter is moving only in the horizontal direction.

cookiemonster
 

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