How Does the Metric Affect Index Position in Tensor Contractions?

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Homework Help Overview

The discussion revolves around the role of the metric in raising and lowering indices within the context of tensor contractions in General Relativity (GR). Participants are examining specific expressions involving the Kronecker delta and derivatives of a vector field.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants are questioning which index the metric will raise in the expression \(\delta^{ij} \partial_i \xi_j\) and whether the resulting forms \(\partial^j \xi_j\) and \(\partial_i \xi^i\) are equivalent. There is also a suggestion that the metric used might actually be \(g^{ij}\) instead of \(\delta^{ij}\).

Discussion Status

The conversation is exploring different interpretations of the tensor expressions and the implications of index manipulation. Some participants have provided clarifications regarding the equality of the expressions under certain conditions, while others are emphasizing the scalar nature of the resulting quantity.

Contextual Notes

There is a potential assumption regarding the use of the Kronecker delta versus the metric tensor, which may affect the interpretation of the problem. The discussion also touches on the order of contractions and their impact on the outcome.

S.P.P
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In GR the metric can raise or lower indices, but which index will it raise in this case:

[itex]\delta^{ij} \partial_i \xi_j[/itex]

is it,

[itex]\partial^j \xi_j[/itex]

or,

[itex]\partial_i \xi^i[/itex]

Or are these equal?
 
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S.P.P said:
In GR the metric can raise or lower indices, but which index will it raise in this case:

[itex]\delta^{ij} \partial_i \xi_j[/itex]

is it,

[itex]\partial^j \xi_j[/itex]

or,

[itex]\partial_i \xi^i[/itex]

Or are these equal?

Didn't you actually mean [itex]g^{ij} \partial_i \xi_j[/itex]??
In that case, yes, it is equal to both the expressions you gave, which are equal to one another.
 
Brilliant, thanks very much! :smile:
 
Note that int both
[itex]\partial^j \xi_j[/itex]
and
[itex]\partial_i \xi^i[/itex]
you will be doing a further contract. What you are really saying is that the order in which the contractions are done does not matter.
[itex]\delta^{ij} \partial_i \xi_j[/itex]
is a scalar quantity.
 

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