Is a 15 A Circuit Breaker Capable of Handling 10.6 A Maximum Current?

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Homework Help Overview

The discussion revolves around the capabilities of a 15 A circuit breaker in relation to a maximum current of 10.6 A. Participants are exploring the implications of circuit breaker ratings and power calculations in an electrical context.

Discussion Character

  • Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants are attempting to determine the maximum current the circuit breaker can handle and the average power it can supply. There is a discussion about the correctness of the formula used to calculate maximum current and whether the average power calculation is accurate.

Discussion Status

Some participants have provided feedback on the calculations, with one noting a potential error in the maximum current formula. There is acknowledgment of the average power calculation being correct, but uncertainty remains regarding the maximum current interpretation.

Contextual Notes

Participants are required to provide answers with three significant digits, and there is an emphasis on ensuring that the maximum current should not be lower than the average current.

cseet
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A circuit breaker is rated for a current of 15 A rms at a voltage of 120 V rms. Answer the following questions:
All answers must have three significant digits unless otherwise specified.

1) What is the largest value of I(max) that the breaker can carry? (Unit: A)

answer:

I(max) = 15(rms) / square root of 2
= 10.6A

2) What average power can be supplied by this circuit? (Unit: kW)

P(rms) = I (rms) * V (rms)
= 1.80 kW

pls correct me if I was wrong and pls direct me to the right path...
thanks
cseet
 
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Argh, stupid me.

I(max) = 15(rms) / square root of 2 is not correct, it should be:
I(max) = 15(rms) * square root of 2 if I'm not mistaken.
 
Last edited:
Hi chen,

what about the 2nd answer? is it correct?

thanks
cseet
 
Yes, 1.8kW. By the way, you could have noticed that your first answer is wrong because the maximum current cannot be lower than the average current. :smile:
 
Thanks Chen... I see that now...
you have a good day
cseet
 

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