
#1
Aug1907, 03:00 PM

P: 1

I am trying to understand how to calculate the torque on a flywheel. If I have a 90 pound flywheel that is 20" in diameter, how do I find the torque?
Thanks for your help. 



#3
Aug2007, 11:56 AM

Mentor
P: 22,001

...ie, torque comes from/causes acceleration/deceleration. So a flywheel at constant speed doesn't have any associated torque.
We'll need to know more about what you want to do. 



#4
Aug2007, 02:15 PM

HW Helper
P: 6,925

Flywheel torque
The angular moment of inertia for a solid disk is m x r^2 / 2 so in this case it's 90 lb (mass) x (10/12 ft)^2 / 2 = 62.5 lb ft^2
1 lb mass = 1 slug / 32.174, so moment of inertia I = 1.94 slug ft^2 Assuming no friction, torque would be associated with a rate of acceleration or deceleration. Assume that flywheel accelerates at a rate of 1000 rpm per second, rate of acceleration is: (1000 revolutions / minute x sec) x (minute / 60 sec) x ( 2 x pi x radians / revolution) = 104.72 radians / sec ^2 = alpha Conversion factors: 1 slug = 1 lb sec^2 / ft Back to example: Torque = alpha(/radians) x I = (104.72 / sec^2) x 1.94 slug ft^2 = (104.72 / sec^2) x 1.94 (1 lb sec^2 / ft) ft^2 = 203.16 ft lb 



#5
Sep607, 05:05 PM

P: 25

Torque is claclulated in absolute units, in this case foot pounds. You have to take into account the angular velocity, and the radius and mass of the flywheel. But here's the interesting thing if you have a flywheel that is two feet in diameter, and apply a force of 1lbwt. to turn the flywheel, the torque experienced at the axle is 1 foot pound. 1lb wt = about 1/32 of a foot pound, so you can see that the greater the diameter of the flywheel the larger the mechanical advantage. You can see why Archimedes was able to say give me a lever that is long enough and I will move the earth or words to that effect. django




#6
Aug1208, 10:16 AM

P: 6

I need help as i am not good at physics, despite formula given by you gentlemen.
I have made a flywheel for a bicycle. What is the torque for 6 kg steel Flywheel? The diameter is 3 1/2" ins by thickness 2 1/2" ins. The weight is 6 kg or 212 ounces ( 13.2 lb Flywheel rpm : 410 rpm ( Pedalling average at 60 rpm ) Yo are a gentleman and a scholar thanks I rally appreciate your help. 



#7
Aug1208, 02:22 PM

Sci Advisor
P: 5,095

Again, as per the previous posts, a flywheel requires no torque at a constant speed like you have mentioned. What exactly do you want to know when you ask for the torque? Are you wanting to know what the flywheel will provide or what it takes to get it to speed?




#8
Aug1208, 02:45 PM

P: 6

Sorry for not stating clearly. I have a flywheel installed on a bike and it runs well. The system provide energy to the pedal when pedaling and it's balance out. Yes, what the flywheel provide? Thanks so much Sir!




#9
Aug1208, 06:16 PM

P: 6

What is the angular velocity and moment of inertia for a flywheel weight of 6 kg ( 212 oz )with the diameter of 3 and 1/2 ins. and rpm is 479




#10
Aug1308, 03:06 PM

P: 6

The crank power is 0.6 Hp ( 450 Watts ) and rotating speed of 100 rpm. A solid disc steel flywheel of 6 kg with a diameter of 3 1/2 ins.( rotates at 547 rpm if this is important ). Can this flywheel provide it's stored energy more than the crank's when release ?
I don't mind anyone correcting me for not understanding flywheel principle, i don't have academic education coming from poor family, I self learn things that fascinates me. Thanks you! 



#11
Aug1308, 05:39 PM

Mentor
P: 22,001

Jeff went through a sample of all of those calculations in post #4. We like to try to get our users to learn instead of just giving answers  give the calculations a shot and see how you do.
One thing though: 



#12
Aug1408, 06:09 AM

P: 6

Thank you Sir, and to all at this site. I am encourage.




#13
Sep2408, 03:58 PM

P: 6

In designing the flywheel, the balancing of crank torque fluctuations produced by pedaling, I see that there is a transfer of energy to the low torque area in the pedal cycle. Thus the pedal is smooth and consistant. In all i wanted to know how it is that the extra weight added to the already heavy bicycle, when pedaling I don't feel the load at the pedal and the back wheel, instead it is light and easy throughout the pedal cycle. So I thought to workout the torque transfer from the flywheel. Perhaps in physics perspective I can see. 



#14
Jan1009, 05:47 AM

P: 265

Hi! edneo,
Torque is calculated as follows: Torque = inertial mass x angular acceleration. It should be simple enough to substitute whatever figures apply in your case to the formula and to work out whatever you need to know. 



#15
Jul2009, 02:10 PM

P: 5

I have to design a flywheel to generate 30 ft lb torque. How do i go about it?




#16
Jul2009, 10:45 PM

Mentor
P: 22,001





#17
Jul2109, 01:24 PM

P: 5

we need the flywheel to run an alternator. the torque requirement of the alternator is 30 ft lb. and the RPM range will be 300~0. the alternator produces 71V and 2.1A at 300RPM and decreases uniformly with RPM. the flywheel should be albe to move the alternator for atleast 15 seconds.
Thank you 



#18
Jul2109, 05:08 PM

P: 5

hello Russ,
thanx for your post. can you suggest any book or link that i can refer and that will help me design the flywheel 


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