Solvng the Mass of an Object with a Vibrating String

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Homework Help Overview

The discussion revolves around determining the mass of an object suspended from a vibrating string, which is influenced by the tension in the string and the fundamental frequency of standing waves. The context includes concepts of wave mechanics and forces acting on the mass.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • The original poster attempts to relate the tension in the string to the weight of the mass and the wave properties. They question whether the weight is half of the tension. Other participants clarify that the tension must equal the weight of the mass to maintain equilibrium.

Discussion Status

Participants are actively engaging in clarifying the relationship between tension and weight. Some guidance has been provided regarding the forces involved, but there is no explicit consensus on the original poster's assumptions.

Contextual Notes

The discussion includes assumptions about the behavior of tension in the string and the effects of the vibrating oscillator, with no resolution on the original poster's queries regarding their assumptions.

new324
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Once, again I find myself in need of a little help. Any hints/tips would be well appreciated.
In the arrangement shown in (attachment), a mass m can be hund from a string (with a linear mass density of .002 kg/m) that passes over an ideal pulley. A string with a length of L=2 meters is connected to a vibrator of constant frequency, Find the mass m of the object when the standing waves with a fundamental frequency of 20 Hz are observed in the string.

Update: Alright I substitued a few equations and have determined the Tension. My assumption is that the mg is going to be half of the tension (half is mg the other half is the wave). Is this assumption correct? If not, any hints?
 

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new324 said:
Update: Alright I substitued a few equations and have determined the Tension. My assumption is that the mg is going to be half of the tension (half is mg the other half is the wave). Is this assumption correct?
Think about it: The tension in the string must support the weight of the mass. Right?
 
No, it's tension=m*g. Look at the situation without a wave: At the end of the string you'll have to pull with a force of m*g to prevent the mass from falling; hence the tension in the whole spring is m*g. If you run the oscillator now (with an arbitrarily small amplitude), this won't change, force can't be "splitted up" into two halfs in the same string.

Bruno
 
Awesome. You guys are such a huge help to me. I always try and make things tougher than they are. Thank You!
 

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