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complex number |
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| Aug27-07, 09:12 AM | #1 |
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complex number
1. The problem statement, all variables and given/known data
find the four fourth roots of -2[tex]\sqrt{3}[/tex]+i2 i dont have any attempt for a solution because i dont know what to do.. im really lost.. i regret sleeping in class 1. The problem statement, all variables and given/known data 2. Relevant equations 3. The attempt at a solution |
| Aug27-07, 09:25 AM | #2 |
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I imagine you were intended to use DeMoivres' theorem:
If a complex number can be written in polar form [itex]z= r(cos(\theta)+ i sin(\theta))[/itex] then its nth power, zn, can be written [itex]z^n= r^n(cos(n\theta)+ i sin(n\theta)[/itex] In your case, n is the fraction 1/4. Convert [itex]-2\sqrt{3}+ 2i[/itex] to polar form (which happens to be pretty simple). Take the real fourth root of r. Remember that you can add any multiple of [itex]2\pi[/itex] to [itex]\theta[/itex]. Dividing by 1/4 will give you different results for different multiples of [itex]2\pi[/itex]. |
| Aug27-07, 10:01 AM | #3 |
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im having some problem in the angle..
what i dis is this z=r cis (theta) x=-2(sqrt3) y=2 r=4 so theta=-60 then, will i just substitute the numbers to the equation? |
| Aug28-07, 05:55 AM | #4 |
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complex number
Yes, of course. r= 4 and theta= - 60 degrees (although I would prefer theta= -[itex]\pi/3[/itex]).
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| Aug28-07, 06:36 AM | #5 |
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i think the angle is is -30...
soln: x=-2(sqrt3) y=2 r=4 tan (theta)= 2/[-2(sqrt3)] =-1/sqrt3=-30degrees=-pi/6 shouldn't I make the angle positive???? if yes should i subtract 30 from 180 or subtract 30 from 360? i'm totally clueless... desperately needing some help |
| Aug28-07, 07:56 AM | #6 |
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pls pls pls...help me with this one..can anyone give me a complete solution for this???thanks
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| Aug28-07, 08:17 AM | #7 |
Recognitions:
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It looks to me like your angle is more like 150 degrees. You are in the second quadrant. So yes, subtract it from 180.
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