Solving an Equation with a K-Map: Can You See Where I Went Wrong?

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SUMMARY

The discussion centers on simplifying the Boolean equation F = A'C' + A'BC + B'C using a Karnaugh map (K-map). The user initially simplified the equation to F = A' + B'C but encountered a logical inconsistency when analyzing the terms. The correct interpretation reveals that F should be expressed as F = A'(C' + BC) + B'C, clarifying the misunderstanding regarding the terms involved.

PREREQUISITES
  • Understanding of Boolean algebra and simplification techniques
  • Familiarity with Karnaugh maps (K-maps)
  • Knowledge of logical operators (AND, OR, NOT)
  • Basic concepts of digital logic design
NEXT STEPS
  • Study the principles of Boolean algebra for advanced simplification techniques
  • Learn how to construct and interpret Karnaugh maps effectively
  • Explore common pitfalls in Boolean simplification and how to avoid them
  • Review digital logic design concepts related to combinational circuits
USEFUL FOR

This discussion is beneficial for students of digital logic design, educators teaching Boolean algebra, and anyone involved in circuit design who needs to understand K-map simplifications.

Xkaliber
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Homework Statement



F = A'C' + A'BC + B'C

The Attempt at a Solution



I put the above equation into a k-map and it simplified down to F = A' + B'C. Pretty easy.

Well, after looking at the equation, that would seem to require that (C'+BC) = 1 since F = A'(C'+B'C) + B'C. However, if C = 1 and B = 0, then C'+BC = 0.

Can anyone see where I went wrong?
 
Last edited:
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sure:
It is F = A'(C'+BC) + B'C
NOT F = A'(C'+BC) + BC
 

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