
#1
Sep1807, 01:04 PM

P: 19

1. The problem statement, all variables and given/known data
David is driving a steady 31.0 m/s when he passes Tina, who is sitting in her car at rest. Tina begins to accelerate at a steady 2.80 m/s^2 at the instant when David passes. How far does Tina drive before passing David? What is her speed as she passes him? 2. Relevant equations 3. The attempt at a solution I know that there is two different cars moving seperatly and they will need two different equations, but im not sure exactly how to go about this one? 



#2
Sep1807, 01:14 PM

Sci Advisor
HW Helper
P: 8,961

For the steady car s=vt, for the accelarating one s=ut+1/2at^2




#3
Sep1807, 05:28 PM

P: 19

OK im just not sure what do with the equations, and what is s representing in these equations?




#4
Sep1807, 05:51 PM

P: 2

Kinematic problem help!!!!If you are finding it hard to use the equations directly it's probably because you don't quite know what you're heading for. This may help, or it my not, if both car's movement were mapped onto a distancetime graph would they cross? If so, what does this mean in respect to the equations. ~ Ek. 



#5
Sep1807, 06:22 PM

P: 19

What does u represent in these equations and i am having trouble finding time, what steps do I need to find this?




#6
Sep1807, 06:29 PM

Sci Advisor
HW Helper
P: 8,961

There is a sticky describing the equations ( with better latex formatting).
Generally: s = distance t = time a = acceleration u = initial velocity v = final velocity 


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