## Size and direction of the change in velocity

1. The problem statement, all variables and given/known data
Find Size and direction of the change in velocity:

a)5m/s west to 10 m/s west

b)10m/s west to 5m/s west

c)5m/s west to 10m/s east

2. Relevant equations

3. The attempt at a solution

a)10-5= 5 west

b)5-10=-5 because there isn't size wihe negitve the answer will be 5 to oppicite direction (east)

C) My problem here the book says the answer will be 15 m/s east but I don't how it come up with it ?

can you explain it for me ?

 Quote by coconut88 1. The problem statement, all variables and given/known data Find Size and direction of the change in velocity: a)5m/s west to 10 m/s west b)10m/s west to 5m/s west c)5m/s west to 10m/s east 2. Relevant equations 3. The attempt at a solution a)10-5= 5 west b)5-10=-5 because there isn't size wihe negitve the answer will be 5 to oppicite direction (east) C) My problem here the book says the answer will be 15 m/s east but I don't how it come up with it ? can you explain it for me ?
5m/s west is equal to -5m/s east.
 Think you FedEx 5m/s west to 10m/s east = 15 m/s east here my problem From where I can get 15? why does the book add them?even I know that if I want to know finall velocity v2-v1 but here v2+v1 why ????????

## Size and direction of the change in velocity

 Quote by coconut88 Think you FedEx 5m/s west to 10m/s east = 15 m/s east here my problem From where I can get 15? why does the book add them?even I know that if I want to know finall velocity v2-v1 but here v2+v1 why ????????
(10m/s east) - (5 m/s west) = (10 m/s east) - (- 5m/s east) = 15 m/s east