Why do 2 balls bounce in a Newton's Cradle instead of just one?

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SUMMARY

The discussion centers on the mechanics of Newton's Cradle, specifically why two balls bounce out instead of one when two are lifted and released. This phenomenon is explained through the principles of elastic collisions, where both kinetic energy and momentum are conserved. The mathematical reasoning shows that if two balls, each with mass m and velocity v, collide, their combined momentum (2mv) and kinetic energy (mv²) must be maintained post-collision. The conclusion is that the only valid outcome is that two balls result in two balls bouncing out, a principle that is foundational in physics and observable in other scenarios like billiards.

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  • Understanding of elastic collisions in physics
  • Basic knowledge of momentum and kinetic energy conservation
  • Familiarity with Newton's laws of motion
  • Concept of mass and velocity in physics
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  • Study the principles of elastic collisions in detail
  • Explore the conservation of momentum and kinetic energy in various physical systems
  • Investigate real-world applications of Newton's laws, such as in billiards
  • Learn about advanced topics in mechanics, such as inelastic collisions and their implications
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Students of physics, educators teaching mechanics, and anyone interested in understanding the fundamental principles of motion and energy conservation.

Yuc4h
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Hello everyone

There is this device called Newton's Cradle

http://www.heurekashop.fi/files/magneetti/productpics/496picture2Upload.jpg

You lift one ball and let it impact with other balls, the impact is followed by other ball bouncing from the other side.

However, when you lift 2 balls, the impact is followed by 2 other balls bouncing. Why is that? I would initially guess that only one ball bounces, the answer can not be very simple since I actually asked a professor of physics about this and he didn't really know the answer.
 
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The simple answer is that this involves elastic collisions where no deformation occurs. Both kinetic energy and momentum are conserved. When you satisfy both conditions, you get 1 ball = 1 ball, 2 balls = 2 balls, etc as the only possible solution.
 
But also 2 balls = 1 ball would satisfy the conditions if the ball would get twice the momentum and it also would make more sense.
 
Yuc4h said:
But also 2 balls = 1 ball would satisfy the conditions if the ball would get twice the momentum and it also would make more sense.
How would that conserve energy? And why would it make more sense?
 
Both conditions have to be satisfied. If you have 2 balls, each of mass m, moving with velocity v before the collision, the combined momentum is 2mv and the combined kinetic energy is mv^2. After the collision, these must still be true.
If you had only one ball leaving, its momentum would have to be 2 mv. Since its mass is m, its velocity must be 2v. However, that would make the kinetic energy 2mv^2. So, this cannot be a solution.
This is a standard problem in Physics. The solution is well known and accepted. Thousands (millions?) of students have played with Newton's cradles and tried to get a different result. All have failed.
If this solution were not true, it would be impossible to play the game of pool (billiards) as we know it.
 

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