# Dentist Chair

by BuBbLeS01
Tags: chair, dentist
 P: 602 1. The problem statement, all variables and given/known data A dentist's chair of mass 207kg is supported by a hydraulic lift having a large piston of cross-sectional area 1403.0cm^2. The dentist has a foot pedal attached to a small piston of cross-sectional area 78.0cm^2. What force must be applied to the small piston to raise the chair. 2. Relevant equations P=F/A Fp/Ap = Fc/Ac 3. The attempt at a solution Fp = Fc/Ac * Ap Fp = 207kg/1403 * 78 = 112.78 Okay so I have already gotten the answer 112.78N but I don't understand a few things about this question... - Why does Fp/Ap = Fc/Ac?? - Why is 207kg relate to 1403cm^2? - What is the subscripts p and c???
HW Helper
P: 6,202
Suggestion in your calculations when you said...
 Quote by BuBbLeS01 Fp = 207kg/1403 * 78 = 112.78
F=mg...so the force should be the weight..so you have to multiply by 9.81Nkg^-1 or whatever value you take as g and convert the cm^2 to m^2

"Why does Fp/Ap = Fc/Ac??"

Does this not mean that $P_p=P_c$ which just basically says that pressure is transmitted equally throughout a fluid...i.e. the pressure at one end is equal to the pressure at the other.

the subscripts p and c would be piston and chair respectively

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