Register to reply 
Buoyancy in oil/water 
Share this thread: 
#1
Dec507, 02:42 PM

P: 7

1. A solid cylinder (radius = 0.150 m, height = 0.120 m) has a mass of 6.90 kg. This cylinder is floating in water. Then oil ( = 725 kg/m3) is poured on top of the water until the situation shown in the drawing results. How much of the height of the cylinder is in the oil?
2. (p)water(g)(V)water + (p) oil(g)(V) oil= mg (V)water+ (V)oil= (V)cylinder (h)oil= (V)oil/area of cylinder 3. using what i was given, i was able to calculate the area and volume of the cyclinder, which was easy enough. i know that once i use the first equation to get the volume of the oil im supposed to subtract it from the volume of the cylinder. unfortunately im not sure how to figure out the volume of the oil using the equation we were given (the first one i listed) 


#2
Dec507, 02:49 PM

HW Helper
P: 1,982

I can't see any drawing.



#3
Dec507, 03:23 PM

P: 7




#4
Dec507, 04:02 PM

HW Helper
P: 1,982

Buoyancy in oil/water
Total buoyant force upward = weight of water displaced + weight of oil displaced. Is this enough for you to proceed?
Take h as the height of the cylinder in oil. Then Hh is in water, where H is ht of cylinder. Try it out. 


Register to reply 
Related Discussions  
Energy loss converting water to hydrogen then back to water  General Physics  2  
Buoyancy and Density and Buoyancy  General Physics  1  
HELP! relationship between rate of flow of water and height of water column  Introductory Physics Homework  1  
Basic question regarding triple point of water and physical properties of water  Introductory Physics Homework  9  
Buoyancy lab for my physics class  Introductory Physics Homework  4 