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Drop in Concentration as reaction progresses |
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| Dec9-07, 08:20 AM | #1 |
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Drop in Concentration as reaction progresses
1. The problem statement, all variables and given/known data
I am currently doing an investigation into the reaction between different acids and magnesium metal. I want to try and show that by using a large volume of acid the concentration drop as the reaction progresses is significantly reduced. Is there any way of doing this? 2. Relevant equations Mg (s) + 2 HCl (aq) --> H2 (g) + MgCl2 (aq) Mg (s) + 2 H+ (aq) --> H2 (g) + Mg+2 (aq) 3. The attempt at a solution Well I thought that by working out the moles of H+ ions present at the beginning of the reaction and at the end of the reaction may help. Other than that, I would just like to be pointed in the right direction. |
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| Dec10-07, 02:35 PM | #2 |
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You could remove an aliquot of solution at several intervals and titrate the acid. Plot the concentration of acid vs time for your result.
The results might surprise you, though... |
| Dec10-07, 03:14 PM | #3 |
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well, so far I have found out the number of moles of HCL in 100cm3 of acid and then found the number of moles of H+ ions. I then found the percentage drop.
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| Dec10-07, 03:50 PM | #4 |
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Drop in Concentration as reaction progresses
What did you notice about the reaction rate?
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| Dec11-07, 06:03 AM | #5 |
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well, I worked out that the maximum drop in concentration theoretically was 5.20% which for a concentration of 0.8 M is not significant.
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| Dec11-07, 01:17 PM | #6 |
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Thats what I thought would happen. Also, the metal surface area is shrinking during the reaction. This will cause the greatest change in rate of reaction.
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