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proves that... |
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| Dec10-07, 10:59 AM | #1 |
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proves that...
Given a positive whole number n, [tex]\exists[/tex] N with the following property: if A is a subgroup of {1,2,...,N} with at least N/2 elements, then there is a positive whole number m<= N - n such that
|A [tex]\cap[/tex]{m+1, m+2,..., m+k}|>=k/2 [tex]\forall[/tex] k = 1, 2, …, n. |
| Dec10-07, 12:01 PM | #2 |
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Recognitions:
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Just look at the top half and the bottom half.
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| Dec10-07, 01:31 PM | #3 |
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Hi, I'll be glad if you put your solution here. I already saw a proof, but I don't know if it's correct.
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| Dec10-07, 01:33 PM | #4 |
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proves that...
this is an olympic problem, by the way
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