integration by parts.


by annamariesmit
Tags: integration, parts
annamariesmit
annamariesmit is offline
#1
Dec17-07, 11:51 PM
P: 1
how would one integrate by parts the following:
[tex]\int sin^2xdx[/tex]

thanks!
Phys.Org News Partner Science news on Phys.org
Simplicity is key to co-operative robots
Chemical vapor deposition used to grow atomic layer materials on top of each other
Earliest ancestor of land herbivores discovered
rsm
rsm is offline
#2
Dec17-07, 11:58 PM
P: 1
hi
use the fact that sin^2 x = (1-cos2x)/2
from the formula cos2x=1-2sin^2 x

Tell me how you wrote that equation
malawi_glenn
malawi_glenn is offline
#3
Dec18-07, 03:52 AM
Sci Advisor
HW Helper
malawi_glenn's Avatar
P: 4,739
[ tex]\int sin^2xdx[/tex ]

Click on the image (equation) and the TeX code comes up. See also:
http://www.physicsforums.com/showthread.php?t=8997

Aslo this is not a forum for homeworks, http://www.physicsforums.com/showthread.php?t=44101

Post questions regarding homework and similar in the homework section.

HallsofIvy
HallsofIvy is offline
#4
Dec18-07, 05:55 AM
Math
Emeritus
Sci Advisor
Thanks
PF Gold
P: 38,879

integration by parts.


Quote Quote by annamariesmit View Post
how would one integrate by parts the following:
[tex]\int sin^2xdx[/tex]

thanks!
Are you required to use integration by parts? As rsm said, there are simple and standard substitutions for [itex]sin^2(x)[/itex] and [itex]cos^2(x)[/itex].

If you are required to use integration by parts, then, since integration by parts requires a product, the obvious thing to do it write this as a product:
[tex]\int sin^2(x) dx= \int (sin(x))(sin(x) dx)[/tex]
Let u= sin(x) and let dv= sin(x) dx. Then du= cos(x)dx and v= -cos(x)
[tex]\int sin^2 x dx= -sin(x)cos(x)+ \int cos^2(x) dx[/tex]
Now do the same thing with that integral. Of course, what happens is you will get back to your original [itex]\int sin^2(x) dx[/itex]- but with a lot of other things. Solve that equation algebraically for [itex]\int sin^2(x)dx[/itex]


Register to reply

Related Discussions
Integration problems. (Integration by parts) Calculus & Beyond Homework 5
integration by parts Calculus & Beyond Homework 1
integration by parts Calculus 6
Integration by Parts Calculus & Beyond Homework 1
Using Integration by Parts Calculus & Beyond Homework 5