## Simple Harmonic Motion Question

A body oscillates in SHM according to the equation, x = A cos(wt + f) where A = 8.8, ω = 1.070, and φ = 0.420. Assume all quantities are in SI units. What is the period?

I dont know how to get the period from this equation? Can anyone lead me in the right direction, please? Thanks! ~Dave W.
 First, I will re-write your equation to avoid confusion: $$x = Acos(\omega{t} + \phi)$$ where the quantities are as you stated. Now, I can tell you that $$\omega$$ (the angular frequency) is equal to $$2\pi{f}$$, where f is the frequency (number of oscillations per second). From that, can you find the period?
 Kinda. I see that $$f = \frac{1}{T}$$ So, from that, I can write: $$x = Acos(\frac{2\pi}{T}(t) + \phi)$$ Then, I solve for T: but i've now introduced an "x" and a "t" into the problem, where do i go from here?

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## Simple Harmonic Motion Question

 Quote by NanoTech Kinda. I see that $$f = \frac{1}{T}$$
Right!
 So, from that, I can write: $$x = Acos(\frac{2\pi}{T}(t) + \phi)$$
Don't do that! Instead write the equation for ω (which is given) in terms of T. (I know you can do it, since that's what you just did to rewrite that equation.)