How do I solve this line integral problem with given constraints?

Click For Summary
SUMMARY

The discussion centers on solving a line integral defined by the equation ∫_C ((y-z)dx + (z-x)dy + (x-y)dz) over the curve C, constrained by the equations x² + y² + z² = 1 and y = √3x. The user suggests making the substitution y = √3x, which simplifies the curve to 4x² + z² = 1. The integrand is then transformed to ((√3 - 1)∫_C zdx - xdz). The application of Green's Theorem is recommended as a method to evaluate the integral.

PREREQUISITES
  • Understanding of line integrals and their notation
  • Familiarity with Green's Theorem and its applications
  • Knowledge of multivariable calculus concepts
  • Ability to perform substitutions in integrals
NEXT STEPS
  • Study the application of Green's Theorem in line integrals
  • Learn about parameterizing curves in three-dimensional space
  • Explore techniques for evaluating line integrals with substitutions
  • Review examples of line integrals involving spherical coordinates
USEFUL FOR

Students and professionals in mathematics, particularly those studying calculus and vector analysis, as well as anyone preparing for exams involving line integrals and multivariable calculus concepts.

nizama
Messages
10
Reaction score
0
Hi!

I had exam today and i got one task that i am not sure how i should have made it so i hope you can help me with this one

It goes :

Find the line integral (i'm not good with using symbols so i'll do my best here)
integral by line C from (y-z)dx+(z-x)dy+(x-y)dz
int_C ( (y-z)dx+(z-x)dy+(x-y)dz )
and C is given by
(x^2)+(y^2)+(z^2)=1
y=x(sqrt3)

thanx a lot in advance and hope to hear from any of you soon
 
Physics news on Phys.org
If you make the substitution y=(3)1/2x, then you get for C:

4x2+z2=1

and you get for your integrand:

((3)1/2-1)∫Czdx-xdz

I'd use Green's theorem from there.
 
Thank you so much

i will try to work from there :)
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 11 ·
Replies
11
Views
3K
  • · Replies 13 ·
Replies
13
Views
3K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 20 ·
Replies
20
Views
5K