Answer: Calculating Linear Force from 5000 lb-ft of Torque

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SUMMARY

The discussion focuses on calculating linear force from torque, specifically addressing a rotary drive generating 5000 lb-ft of torque. The setup involves a 12" arm extending horizontally from the shaft, with a connecting rod attached perpendicularly. It is established that a torque of 5000 lb-ft translates to a linear force of 5000 lbs at a distance of 1 foot, directed perpendicular to the arm. This relationship is crucial for understanding the mechanics of the linkage system in the context of opening and closing dampers.

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jw2007
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I am working with a rotary drive and a linkage system to open and close dampers. I am having trouble recalling how lb-ft and lbf relate. The drive has a rotating shaft with and arm extending from it. The shaft generates 5000 lb-ft of torque and I need to understand what linear force this applies to a connecting rod attached to the opposite end of the 12" arm extending from the shaft. The rotating shaft is in one end of the 12" arm. The arm is horizontal (on the x-axis) and the connecting rod is attached to the other end of the arm and it perpendicular to the arm (on the y-axis). I hope this is clear. Thanks.
 
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A drive which provides 5000lb-ft of torque will generate 5000 lbs of force at a distance of 1 foot, in the direction perpendicular to your 'arm'.
 
Thank you!
 

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