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force magnetized fluid |
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| Jan27-08, 05:44 AM | #1 |
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force magnetized fluid
The force on a single dipole (dipole moment m) can be obtained by taking the gradient of its energy, i.e.
[tex]\vec{F} = \nabla (\vec{m} \cdot \vec{B})[/tex] One also often encounters for the energy of a magnetized material [tex]-\mu_0 \vec{M}\cdot \vec{H}[/tex] And often the force on a material with magnetization M is written [tex] \vec{F}=\mu_0 M \nabla H[/tex] why the replacement of B with H? Does it have something to do with the fact that part of B is producedby the magnetization (B=mu_0(H+M)) and the material can't excert a force on itself?? Or does one necessarily have to dive into the derivations to get an idea why? Any intuitive thoughts? |
| Jan27-08, 09:03 AM | #2 |
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Do you have a source for your equations with H?
Probably the muzero H just stands for B outside the magnet. |
| Jan27-08, 11:09 AM | #3 |
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The force equation with H (M gradH) (Kelvin force) is the standard expression used in ferrohydrodynamics (see e.g. Rosensweig) when dealing with dilute colloids for example.
I'm wondering if the use of H instead of B results from the fact that only the external applied magnetic field should be used in evalueating the force because the magnetized material cannot exert a force on itself. Any familiarity with these expressions? |
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