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Squareing Matrix(?) in MATLAB |
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| Feb19-08, 09:12 PM | #1 |
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Squareing Matrix(?) in MATLAB
Hello, I've got quick questions.
1. When I have a matrix, x, and try to get different values for each x (given y = (x^2)+b), I get this error. ??? Error using ==> mpower Matrix must be square. 2. x is [1x101] double according to MATLAB and I've had this problem when I was taking derivative as well. I've lost numbers throughout the derivative, which i understands. so x' = [1x100] and x'' = [1x99] and so forth. What's the best way to solve these problems. Thank you. |
| Feb19-08, 09:34 PM | #2 |
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| Feb19-08, 09:54 PM | #3 |
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>> x=sqrt(500/105);
>> a=[0:0.1:100]; >> b=[0:1:100]; >> z=a/(2*(sqrt(3000*15))); >> p=x(sqrt(1-((z)^2))) ??? Error using ==> mpower Matrix must be square. this is not the direct problem but it's basically the same thing. Why am I getting this error? I will hold onto my second question for now. [edit] another question... >> x=A*(exp(-(z*wn*t)))*(sin(wd*t)) ??? Error using ==> mtimes Inner matrix dimensions must agree. everything is numeric except t is in matrix... |
| Feb20-08, 04:13 AM | #4 |
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Squareing Matrix(?) in MATLAB |
| Feb20-08, 06:26 AM | #5 |
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thanks a lot! i've got another question...sorry.
i am given that function and there are two independent variables, t and a, which i posted above. i am told that it's initial displacement is zero but it "dies out" after about t=2. so basically, after x has been graphed up to t<2 and when t hits 2 seconds mark, i think everything converges to zero i believe. i tried everything without using mfile but i couldnt figure out so i thought i should use mfile instead so i've retyped everything under... t=[0:0.1:10]; b=[0:1:100]; if 0=<t<2 (BTW, if i want less than equal to 0, i should use =< instead of <= right?) all the components that vary by a and b goes under if statement including equation of x else x=0 end plot(t,x) that's what i've tried but it doesnt seem like i am getting what i wanted. it graphes entire 10s and under mfile, it states something like i can't use this, "0=<t<2", because it's in matrix form but i can't think of any other way to approact this problem. i've thought about while loop and etc. but it seems like that my if,while,and other statements are not working because of how t is in matrix. i really appreciate your help. |
| Oct15-09, 11:18 AM | #6 |
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Hi I'm trying to integrate a function func1 in Matlab but I keep getting errors I realy don't know what I'm doing wrong. Can anyone tell me?
Here is the code Im using: function [ f1 ] = func1( E, Delta, kB, Temp ) %func1: calculates integrand for eqn 1 % Detailed explanation goes here f1=(tanh(sqrt(((E*E)+(Delta*Delta))))/(2*kB*Temp))/(2*(sqrt(((E*E)+(Delta*Delta))))); end Command line code: >> hbar=1.054E-34; Tdebye=420; h=6.626E-34; kB1= 1.38065E-23; >>fdebye=(Tdebye*kB1)/h; >> Temp1=0.5; >> Delta1=0; >> a=hbar*fdebye; >> Q=quad(@(E1)func1(E1,0,1.38065E-23,0.5),-a,a) ??? Error using ==> mtimes Inner matrix dimensions must agree. Error in ==> func1 at 4 f1=(tanh(sqrt(((E*E)+(Delta*Delta))))/(2*kB*Temp))/(2*(sqrt(((E*E)+(Delta*Delta))))); Error in ==> @(E1)func1(E1,0,1.38065E-23,0.5) Error in ==> quad at 77 y = f(x, varargin{:}); |
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