Analyzing Motion: Dog Chasing Rabbit

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Discussion Overview

The discussion revolves around a hypothetical scenario involving a dog chasing a rabbit, focusing on the mathematical modeling of their motion. Participants explore whether the dog can catch the rabbit given their respective positions on the x and y axes and their constant velocities. The conversation touches on theoretical implications, potential modeling approaches, and various conditions affecting the outcome.

Discussion Character

  • Exploratory
  • Technical explanation
  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • Some participants suggest that the dog will never catch the rabbit because it cannot cross the y-axis, leading to an increasing distance in the y component.
  • One participant proposes a modeling approach using coordinates and finite time increments to simulate the motion of both the dog and the rabbit.
  • Another participant questions if there is a more elegant solution to the problem.
  • There are considerations about the initial positions of the rabbit, such as starting below the x-axis, which may change the dynamics of the chase.
  • Participants discuss the implications of the angle between the dog and rabbit's paths and how it relates to other mathematical problems, such as the ladder problem.
  • One participant expresses uncertainty about whether the dog can catch the rabbit unless they start on the same line moving toward each other.
  • Another participant suggests that the proper solution involves finding the position functions for both animals over time.

Areas of Agreement / Disagreement

Participants generally disagree on whether the dog can catch the rabbit, with multiple competing views on the conditions that affect the outcome. The discussion remains unresolved, with various hypotheses and modeling approaches presented.

Contextual Notes

Limitations include assumptions about constant velocities and the initial positions of the dog and rabbit. The discussion does not resolve the mathematical steps necessary for a definitive conclusion.

Ebolamonk3y
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Hello... I am new to the forum...

I just took part in the TN math comptetion today at University of Memphis and I had a few questions that I could not solve...

In particular...

Let [tex]f(x)=\sqrt{x+\sqrt{0+\sqrt{x+\sqrt{0+\sqrt{x...}}}}}[/tex]... ad inf...
If [tex]f(a)=4[/tex], what is [tex]f'(a)[/tex]?

____________________________

Just a general problem

____________________________

A dog sees a rabbit. Position of the dog is somewhere on the x-axis, the rabbit, on the y-axis... At this time, the dog moves directly towards the rabbit as the rabbit runs up the y-axis... if both the dog and the rabbit travel at some constant velocity V, does the dog catch the rabbit? If so, where? If not, why not? And how does one model this function?



Thats all for now...

Chang
 
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for the first one note that f^2 = x + stuff, and then after manipulation, that (f^2-x)^2 = f you can now differentiate put x=a in and you're done.
 
Change,

The rabbit gets away! The dog will never cross the y axis, so he will always have an x component of velocity, so the y component of his velocity will have to be less than 1, so the y component of the distance between him and the rabbit will always be increasing.

To model this?
Define the location of the dog as (Xd, Yd)
Define the location of the rabbit as (Xr, Yr)
Define a finite increment of time, t, for the model.

start>>In one time increment the dog's x and y coordinates will change by delta_x and delta_y which are calculated from sqrt((delta_x)^2 + (delta_y)^2) = vt and delta_y/delta_x = (Yr-Yd)/(Xr-Xd).
Yd = Yd +delta_y
Xd = Xd + delta_x
Yr = Yr+vt
print sqrt((Yr-Yd)^2 + (Xr-Xd)^2).
n=n+1
if n= a billion then stop
goto start
 
Is there a more elegant solution?
 
jdavel said:
The rabbit gets away! The dog will never cross the y axis, so he will always have an x component of velocity, so the y component of his velocity will have to be less than 1, so the y component of the distance between him and the rabbit will always be increasing.

What if the rabbit starts below the x-axis?
 
how does that affect the situation any? he crosses the x but never the y...


Is there some exceptions to this case?


like what if...

the dog is on x and the rabbit is in the negative y-axis running to positive y infinity... And the Dog is mad close to the x=0... the the dog points to the rabbit and its almost like a headon collision but it cannot be because the angle dog nose makes with y-axis as dog goes to rabbit approaches 0... On the other hand... if they start the same distance away from the origion on their respective axises and rabit goes to positive inf and dog goes to rabbit... then its alright...


Another thing to ponder... Are things reversable?

Like...

[tex]\int\frac{1}{x^2}dx[/tex] from 1 to infinity... is just 1...

Say is some work function were the same... you keep walking infinite distance and you still get only 1 joule?! arg... :(
 
Ebolamonk asked: "What if the rabbit starts below the x-axis?"

Hadn't thought of that!

This is looking like a more interesting problem than I had originally thought. Unless the dog and rabbit start on the same line going toward each other, I don't think the dog can ever catch the rabbit by always running toward the rabbit. But I'm not sure!
 
Ebolamonk3y said:
how does that affect the situation any? he crosses the x but never the y...

Yes, but the remark I was replying to said that the y component of the distance between them was always increasing...that isn't true if the rabbit starts below the y axis.

The proper way to solve this would probably be to find the position functions for the rabbit and dog (where time is a parameter). Then just find the time where the functions are equal (if such a time exists).
 
This belongs on the darn Diffy Q forum :(

But anyways...

Does the angle of the between the Dog and Rabbit resemble the angle of the ladder problem if the ladder were to "slip" up? Like you push the ladder towards the Y axis from some point on x... [tex]\frac{dx}{dt}[/tex] is negative something and decreases like the graph of say... 1/x or something like that... arg... maybe I am confusing someone out there.. maybe not!
 

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