Applications of Dot Product: Finding Force Components on an Inclined Plane

Click For Summary
SUMMARY

The discussion focuses on applying the dot product to resolve forces acting on a crate on an inclined plane. Specifically, a 125 N force is applied at a 40-degree angle to the ramp, resulting in a force of 95.8 N in the direction of motion. Additionally, when the ramp is at a 20-degree angle, the force required to lift the crate vertically is calculated to be 108.3 N. The key equations used include the dot product formula, u (dot) v = |u||v|cosx, and the resolution of forces into their x and y components.

PREREQUISITES
  • Understanding of vector operations, specifically the dot product.
  • Knowledge of trigonometric functions, particularly sine and cosine.
  • Familiarity with free body diagrams (FBD) and static equilibrium concepts.
  • Basic principles of forces on inclined planes.
NEXT STEPS
  • Study the application of the dot product in physics problems involving forces.
  • Learn how to construct and analyze free body diagrams for various scenarios.
  • Explore the principles of static equilibrium and how they apply to inclined planes.
  • Investigate the effects of different angles on force components in physics problems.
USEFUL FOR

This discussion is beneficial for physics students, educators, and anyone interested in understanding the application of vector mathematics in real-world scenarios, particularly in mechanics involving inclined planes.

Macleef
Messages
30
Reaction score
0

Homework Statement



15) In Question 14, if the ramp makes an angle of 20 degrees with the level ground. Find the magnitude of the force tending to lift the crate vertically.

Textbook Answer for Question 15: 108.3 N

----

14) A crate is being dragged up a ramp by a 125 N force applies at an angle of 40 degrees to the ramp. Find the magnitude of the force in the direction of motion (Answer is 95.8 N).

-----

Homework Equations



u (dot) v = |u||v|cosx

The Attempt at a Solution



I have half of the diagram because I don't understand the rest of the problem:

2czu7hl.png
 
Last edited by a moderator:
Physics news on Phys.org
draw a box on the ramp;
in FBD= W points down and your points up in +ve y ...
and box is stationary so Fnet = 0
 
What? I don't understand what you meant by "in FBD= W points down and your points up in +ve y"
 
i meant your force, that is asked, and W is the weight of the box
ops, sorry I missed force ><

and then this leaves you with a simply geometric problem where you find the thetas, and something simple like Fx = F.cos theta and Fy = F.sin theta
(it isn't much of dot product problem, but just dividing the F into x and y components )

This is a very common example and you can find a related example in your book too ^_^
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
6K
  • · Replies 1 ·
Replies
1
Views
7K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 7 ·
Replies
7
Views
6K
  • · Replies 1 ·
Replies
1
Views
4K
  • · Replies 13 ·
Replies
13
Views
2K
  • · Replies 2 ·
Replies
2
Views
7K
  • · Replies 2 ·
Replies
2
Views
4K
Replies
11
Views
28K
  • · Replies 3 ·
Replies
3
Views
2K