Finding Coefficient of x^25 in (2x - (3/x^2))^58

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SUMMARY

The coefficient of x^25 in the expression (2x - (3/x^2))^58 is calculated using the binomial theorem. The correct value is determined by evaluating the expression (58 choose k) * (2)^(58-k) * (-3)^k, where k is found to be 11. Substituting k into the equation yields the coefficient as -5676647367067636376814212874240. This confirms that the calculation process was followed accurately, resulting in a large but correct coefficient.

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I get a number that is too big when I calculate the coefficient of x^25 in:

(2x - (3/x^2))^58

This is how I found the coefficient:

Code:
Note that (58) = A combination value...
           k

(58) * (2x)^(58-k) * (-3/x^2)^k
 k
(58) * (2)^(58 - k) * (x)^(58 - k) * (-3)^k * (1/x^2)^k
 k
(58) * (2)^(58 - k) * (-3)^k * (x)^(58 - k) * (x)^-2k
 k
(58) * (2)^(58 - k) * (-3)^k * (x)^(58 - 3k)
 k

58 - 3k = 25
-3k = -33
k = 11

So:

(58) * 2^47 * (-3)^11 * (x)^25
 11

This comes out to be a gigantic number. So I am unsure whether it is anywhere close to being correct despite that I thought that I followed the steps correctly. : \
 
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Thats the right answer; -5676647367067636376814212874240
 

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