Optimizing Sum of Squares with Two Positive Numbers

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SUMMARY

The discussion focuses on finding two positive numbers that sum to 100 while minimizing the sum of their squares. The optimal solution is determined to be 50 and 50, resulting in a minimum sum of squares equal to 5000. The participants clarify that while the problem can be approached heuristically, a formal proof using calculus is not necessary to establish that the minimum occurs when both numbers are equal. The mathematical expression (x+a)² + (x-a)² = 2(x² + a²) is highlighted as a method to demonstrate this minimum condition.

PREREQUISITES
  • Understanding of basic algebraic expressions
  • Familiarity with the concept of optimization in mathematics
  • Knowledge of symmetry in mathematical problems
  • Basic understanding of calculus (optional for proof)
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  • Study optimization techniques in algebraic functions
  • Learn about the properties of symmetric functions
  • Explore calculus methods for finding minima and maxima
  • Investigate real-world applications of optimization problems
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Mathematicians, students studying algebra and optimization, educators teaching mathematical concepts, and anyone interested in problem-solving strategies involving sums and squares.

Agent_J
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Find 2 positive numbers whose sum is 100 and the sum of whose squares is a minimum. Also, find the minimum sum.

I'm not sure how to write mine, but I just tested 99^2 + 1^2 = 9802
then I tested 50^2 + 50^2 = 5000, so obviously its 50 and 50. Also, I don't understand "find the minimum sum", is it just 50 + 50?
 
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who says you are only allowed to consider integers? moreover finding the minimum of x^2+y^2 subject to x+y = 100, and x,y>=0 does not tell you what the minimum is, only where it occurs, when you find the x and y, you are then expected to find the value at that point. as it happpens your guess of 50 and 50 is correct. heuristically, since the question is completely symmetric in x and y an optimum will occur at x=y, however you only believe it to be a minimum at the moment and you need to prove it, say using calculus.
 
You don't need calculus.

(x+a)2+(x-a)2=2(x2+a2), which is minimum when a=0, for fixed x (=50).
 

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