Understanding Waves: Period, Frequency, and Speed of a Vibrating String

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SUMMARY

The discussion focuses on calculating the period, frequency, and speed of waves on a vibrating string that is 50.0 cm long and under a tension of 1.00 N. The strobe rate is set at 5000 flashes per minute, leading to a calculated period of approximately 0.098 seconds. The string vibrates in the second harmonic mode, and the wave speed can be derived using the formula v = √(T/(M/L)), where T is tension and M/L is mass per unit length. The participants emphasize the importance of understanding wave functions and their derivatives for further calculations.

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  • Understanding of wave mechanics and harmonic motion
  • Familiarity with stroboscopic photography and its application in physics
  • Knowledge of wave speed calculations using tension and mass per unit length
  • Ability to differentiate wave functions to find velocity
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  • Learn about wave function derivatives and their physical interpretations
  • Study the relationship between tension, mass, and wave speed in strings
  • Explore the concepts of harmonics and normal modes in vibrating strings
  • Investigate stroboscopic techniques for analyzing wave motion
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Physics students, educators, and anyone interested in wave mechanics, particularly in the context of vibrating strings and harmonic motion.

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I have what I believe to be a simple question. I've looked in the book and lecture notes and couldn't find any help, so whatever you've got would be appreciated.

A vibrating string 50.0cm long is under a tension of 1.00 N. The results from five successive stroboscopic pictures are shown in Fig. 15.34. The strobe rate is set at 5000 flashes per minute and observations reveal that the maximum displacement occurred at flashes 1 and 5 with no other maxima in between.
a)Find the period, frequency, and wavelength for the traveling waves on this string.


I don't have a scanner, but fig 15.34 shows what looks like 5 simple sin graphs. They look like this order:

1)sin(x)
2).5sin(x)
3)sin(0)
4).5sin(-x)
5)sin(-x)

My guess for period looks like this:
5000/60 = 83.3 flashes/sec
5flashes/83.3 = .06 seconds = period

I'm pretty sure that's wrong, but its all I could come up with. If somebody helps me get the period, I can handle the rest.


b) In what normal mode (harmonic) is the string vibrating?

Since in fig 15.34 they only intersect at one point, it is operating in the second harmonic.

c) What is the speed of the traveling waves on the string

With wavelength and frequency, I can easily find this.

d) How fast is point P moving when the string is in: position 1 and position 3?

P is at the crest of the graph of sin(x). I'm pretty sure I just need to find the transversal velocity here, so that shouldn't be much of a problem. Set up the wave function and take the partial derivative w.r.t. to time.

e) What is the mass of the string?

I could use a little help on this one.

Thats it. Any and all help will be appreciated.
 
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Actually, with a little more thought, I'm pretty sure that I need to multiply my period by 2 in order to get a full period. So my period ends up being .12 seconds. Am I right?
 
midgey said:
I don't have a scanner, but fig 15.34 shows what looks like 5 simple sin graphs. They look like this order:

1)sin(x)
2).5sin(x)
3)sin(0)
4).5sin(-x)
5)sin(-x)
I will assume you meant to write:
1)sin(x)
2).5sin(x)
3)0sin(x)
4)-.5sin(x)
5)-sin(x)

And how much of a sine wave is depicted? I assume (based on your later comments) from 0 to 2π radians?

My guess for period looks like this:
5000/60 = 83.3 flashes/sec
5flashes/83.3 = .06 seconds = period
First find the time between flashes: 60 sec/ 5000 flashes = 0.012 sec; so the time between flash 1 and flash 5 would be 4 x 0.012 = 0.048 sec. And, assuming I understand what you've been saying, that will be half the period, so period = 0.098 sec.
e) What is the mass of the string?

I could use a little help on this one.
Once you've found the speed (v) of the wave on the string, you need to relate that to the tension and mass of the string:
[tex]v = \sqrt{\frac{T}{(M/L)}}[/tex]
Where T = tension, M/L = mass per unit length of string. You can solve for the mass.
 

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