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Diffraction grating |
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| Mar20-08, 06:21 PM | #1 |
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Diffraction grating
1. The problem statement, all variables and given/known data
The light shining on a diffraction grating has a wavelength of 488 nm (in vacuum). The grating produces a second-order bright fringe whose position is defined by an angle of 8.02°. How many lines per centimeter does the grating have? 2. Relevant equations d sin q = nl 3. The attempt at a solution d = (2)(488)/sin(8.02) = 6995.474955 d = 1/N N = 1/d = 1/6995.474955 =1.429495505X10^-4 (per M) X 100 = 0.014294955 It got this answer and it is wrong, I have no idea where to go from here or what to do and would be grateful of any help, thanks! |
| Mar20-08, 06:39 PM | #2 |
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You should convert the wavelength from nanometers to meters (or cm, whatever). I don't think you did that properly.
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