# Gibbs Free energy

by jin.cao
Tags: energy, free, gibbs
 P: 13 1. The problem statement, all variables and given/known data CaCO3 <-> CaO + CO2 At 900K, equilibrium pressure of CO2 is 0.0423 atm. Calculate Gibbs Free energy of Reaction and K. 2. Relevant equations delta G = -RTlnK 3. The attempt at a solution delta G = 5656.3 cal/mol K = 0.0423 I have a feeling that this is incorrect Could someone confirm/clarify for me Thanks
 P: 2 I'm not sure what the pressure has to do with it..
 Sci Advisor HW Helper PF Gold P: 2,532 The equilibrium pressure of CO2 is directly connected to the $\Delta G$ of the reaction. If the forward reaction is strongly favored, the pressure is higher, and vice versa.
P: 2

## Gibbs Free energy

ok, but does the pressure have anything to do with the calculations?

delta G = [sum(delta G formation, products) - sum(delta G formation, reactants)]

which can all be calculated from table values.

Then the equation:

delta G = -RTlnK can be used to find K

is this correct?

 Related Discussions Introductory Physics Homework 8 Biology, Chemistry & Other Homework 2 Advanced Physics Homework 3 Introductory Physics Homework 2 Classical Physics 2