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Gibbs Free energy |
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| Mar30-08, 07:47 AM | #1 |
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Gibbs Free energy
1. The problem statement, all variables and given/known data
CaCO3 <-> CaO + CO2 At 900K, equilibrium pressure of CO2 is 0.0423 atm. Calculate Gibbs Free energy of Reaction and K. 2. Relevant equations delta G = -RTlnK 3. The attempt at a solution delta G = 5656.3 cal/mol K = 0.0423 I have a feeling that this is incorrect Could someone confirm/clarify for me Thanks |
| Apr1-08, 10:30 AM | #2 |
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I'm not sure what the pressure has to do with it..
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| Apr1-08, 02:01 PM | #3 |
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The equilibrium pressure of CO2 is directly connected to the [itex]\Delta G[/itex] of the reaction. If the forward reaction is strongly favored, the pressure is higher, and vice versa.
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| Apr1-08, 04:40 PM | #4 |
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Gibbs Free energy
ok, but does the pressure have anything to do with the calculations?
delta G = [sum(delta G formation, products) - sum(delta G formation, reactants)] which can all be calculated from table values. Then the equation: delta G = -RTlnK can be used to find K is this correct? |
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