Register to reply

Gibbs Free energy

by jin.cao
Tags: energy, free, gibbs
Share this thread:
Mar30-08, 07:47 AM
P: 13
1. The problem statement, all variables and given/known data
CaCO3 <-> CaO + CO2
At 900K, equilibrium pressure of CO2 is 0.0423 atm. Calculate Gibbs Free energy of Reaction and K.

2. Relevant equations
delta G = -RTlnK

3. The attempt at a solution

delta G = 5656.3 cal/mol
K = 0.0423

I have a feeling that this is incorrect
Could someone confirm/clarify for me

Phys.Org News Partner Science news on
Scientists develop 'electronic nose' for rapid detection of C. diff infection
Why plants in the office make us more productive
Tesla Motors dealing as states play factory poker
Apr1-08, 10:30 AM
P: 2
I'm not sure what the pressure has to do with it..
Apr1-08, 02:01 PM
Sci Advisor
HW Helper
PF Gold
Mapes's Avatar
P: 2,532
The equilibrium pressure of CO2 is directly connected to the [itex]\Delta G[/itex] of the reaction. If the forward reaction is strongly favored, the pressure is higher, and vice versa.

Apr1-08, 04:40 PM
P: 2
Gibbs Free energy

ok, but does the pressure have anything to do with the calculations?

delta G = [sum(delta G formation, products) - sum(delta G formation, reactants)]

which can all be calculated from table values.

Then the equation:

delta G = -RTlnK can be used to find K

is this correct?

Register to reply

Related Discussions
Gibbs Free Energy of Van Der Waals Gas Introductory Physics Homework 8
Gibbs Free Energy Biology, Chemistry & Other Homework 2
Gibbs free energy Advanced Physics Homework 3
Gibbs Free energy Introductory Physics Homework 2
Gibbs free energy Classical Physics 2