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Stokes Law, Viscosity. (very simple) |
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| Mar30-08, 01:32 PM | #1 |
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Stokes Law, Viscosity. (very simple)
I'm trying to find the viscosity of some glycerol that we dropped various steel balls down using the equation:
V = [2r^2 (p – σ) g] / 9η I put in these values: p = 7800 kg m-3 σ = 1200 kg m-3 g = 9.8 m s-2 And ended up with the equation. η = 129360r^2 / 9V My problem is that I thought viscosity is a constant. When I put my values in the viscosity decreases as radius decreases. |
| Mar30-08, 01:46 PM | #2 |
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Viscosity is constant for constant temperature, but the coefficient of drag is dependent on size.
http://www.grc.nasa.gov/WWW/K-12/airplane/drageq.html There is momentum exchange normally as well as by shear (viscous effects). |
| Mar30-08, 01:52 PM | #3 |
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Ok thanks, so i must've made a mistake somewhere...
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