Verify Answer- Porsche Power Question

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Homework Help Overview

The discussion revolves around the performance characteristics of a Porsche 944 Turbo, specifically focusing on the calculations of maximum acceleration and speed based on engine power and frictional forces. Participants are analyzing the implications of power loss in the drivetrain and the effects of weight distribution on performance metrics.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the calculations for maximum acceleration and question the assumptions regarding power loss in the drivetrain. There is also a debate about the definition of maximum speed in relation to engine power and gearing.

Discussion Status

The conversation is ongoing, with some participants affirming the calculations while others raise concerns about the assumptions made regarding drivetrain losses and the conditions under which maximum speed is determined. Multiple interpretations of the problem are being explored.

Contextual Notes

There are mentions of potential discrepancies in the assumptions about drivetrain losses, with some suggesting a lower percentage than originally stated. Additionally, the weight distribution of the vehicle is being questioned, as well as the relevance of gearing to the calculations presented.

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A Porsche 944 Turbo has a rated engine power of 217 hp (161882 W). 70% of the power is lost in the drive train, and 30% reaches the wheels. The total mass of the car & driver is 1480 kg, and two thirds of the weight is over the drive wheels.

What is the max acceleration if the coefficient of static friction is 1?

(2/3)(1480 kg)(9.80)*1= 9669.33 N Force of static friction

Set this = to mtotal* a 9669.33N=(1480)a a= 6.53 m/s^2

What is the speed of the Porsche at max power output?

P=Fv

F= 9669.33 N P= (161882 W) * (.70) = 113317.4 W

113317.4= (9669.33 N)v
v=11.72 m/s which is about 26.2 mph Does this seem fast enough?
 
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The calculation of acceleration is correct, but the second question is not well defined.
The speed you calculated is the maximum speed when the acceleration is still limited by friction and not by engine power, but even this is true only if one gear is set to maximize power at that speed (the engine's power depends on rpm).
 
You original statement needs to be revised to read 30% loss in drive train, 70% reaches the wheels. Your calculations seem correct, assuming the car is geared so that max power occurs at an acceleration rate of 1 g. However, the second question isn't worded to state that the same gearing used for max acceleration of 1g would be used for determining the car's speed at max power. It would have been better stated to ask for the maximum speed that the maximum acceleration of 1g occurs at.

30% seems a little high for drive train losses, generally it's usually around 15%, although an all wheel drive car could have higher drive train losses.
 
Jeff Reid said:
Your calculations seem correct, assuming the car is geared so that max power occurs at an acceleration rate of 1 g. QUOTE]
This assumption has nothing in common with our problem.
 
so much so wrong
thats a problem with numbers out side the real world
a 26.2 mph sports car ??

a porsche 944 is far closer to the idea 50/50 weight front rear
power loss is about 15%
and they top 140 mph
 

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