How Is the Electric Field Calculated Outside a Cylindrical Conductor?

[jreinier]

I'm trying to find the equation for an electric field at a point outside of a cyllindrical conductor. Any help would be greatly appreciated!

 

[Doc Al]

Use Gauss's law

Assuming you are talking about an infinite conductor with a given charge per unit length, why not just use Gauss's Law to figure it out? (I guess you could always just look it up. It will take you approximately 5 seconds to Google it. But if you know Gauss's law, it's almost as fast to figure it out for yourself. And more fun.)

 

[M98Ranger]

The equation for the electric field at a point outside of a cylindrical conductor can be derived using Gauss's Law. This law states that the electric flux through a closed surface is equal to the enclosed charge divided by the permittivity of free space (ε0).

In the case of a cylindrical conductor, the electric field will be radial and have a constant magnitude at all points outside the conductor. This is due to the symmetry of the cylindrical shape.

Using a cylindrical Gaussian surface, which is a cylinder with its axis coinciding with the axis of the conductor, we can apply Gauss's Law to find the electric field at a point outside the conductor.

The electric field at a point outside the conductor will be given by the equation:

E = (λ/2πε0r)

Where λ is the linear charge density of the conductor and r is the distance from the center of the conductor to the point where the electric field is being measured.

I hope this helps in your understanding of the electric field around a cylindrical conductor.