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expectation values and operators. |
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| May17-08, 06:39 PM | #1 |
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expectation values and operators.
i'm just not sure on this little detail, and its keeping me from finishing this problem.
take the arbitrary operator [tex]\tilde{p}^{n}\tilde{y}^{m}[/tex] where p is the momentum operator , and x is the x position operator the expectation value is then <[tex]\tilde{p}^{n}\tilde{y}^{m}[/tex] > is this the same as <[tex]\tilde{p}^{n}[/tex]> <[tex]\tilde{y}^{m}[/tex]>? if not, how would i go about calculating <[tex]\tilde{p}^{n}\tilde{y}^{m}[/tex] >? |
| May18-08, 04:08 AM | #2 |
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In general, they are not the same. The expectation value of an operator [itex]\hat A[/itex] is
[tex]\int \Psi^*(x) \hat A(x) \Psi(x) \, \mathrm{d}x[/tex] where [itex]\Psi(x)[/itex] is your wavefunction (assuming you are talking QM here). In this case, [tex]\int \Psi^*(x) \hat p^n \hat y^m \Psi(x) \, \mathrm{d}x \neq \left( \int \Psi^*(x) \hat p^n \Psi(x) \, \mathrm{d}x \right) \left( \int \Psi^*(x) \hat y^m \Psi(x) \, \mathrm{d}x \right). [/tex] You could write out [itex]\hat p[/itex] in the position basis and work out what [itex]\hat p^n(y^m \Psi)[/itex] looks like. |
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