# normal one-forms

by Mmmm
Tags: normal, oneforms
P: 63
I'm reading through Schutz's first course in relativity book and am finding question 12 on page 83 a bit problematic.

If I understand it correctly an normal one-form to a plane is a one-form that, when operating on a normal vector to the plane, will give the result 0. This seems fairly straight forward to me.
The question is talking about the plane x=0.
So all vectors normal to this must be of the form (a,0,0) (ie parallel to the x axis)
In that case, the normal one form must have components (0,b,c) then
$$\tilde{n}(\vec{V})= 0*a+b*0+c*0=0$$

Part (c) of the question says
 Show that any normal to S is a multiple of $$\tilde{n}$$
 On the Cartesian basis, the components of $$\tilde{n}$$ are (0,0,$$\beta$$) for some $$\beta$$. Thus any $$\tilde{n}$$ is a multiple of any other.
But my understanding is that (0,0,$$\beta$$) is just a subset of all possible normal one forms to this plane, and I'd agree that of this subset any $$\tilde{n}$$ is a multiple of any other. But this isn't true for all $$\tilde{n}$$, as surley (0,$$\alpha, \beta$$) is also valid.