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Set Builder Notation |
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| Jul30-08, 05:37 PM | #1 |
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Set Builder Notation
Hi!
We have 3 functions; f= , g=[tex]\frac{1}{\sqrt{(2x2 - 1)(x2-1)}}[/tex] and h= [tex]\frac{\sqrt{2+x}+x(x^2-1)}{(x^2-1).\sqrt{2+x}}[/tex]And we want to write the domain of these functions in the set builder notation, which I'm not very familiar with. Well, I know that for the Domain of g, x ≠ 0 and ±1. How do we write it in that notation? is it [0,∞]\{±1}? For the domain of f, x must be greater than or equal to -2 and it cannot equal 0 & ±1 In h, domain: x≥-2, & it can't be ±1 as well. I need to write the domains of these functions in the set builder notation. Not knowing something doesn't mean you're stupid, just asking about it ... ![]() |
| Jul30-08, 06:22 PM | #2 |
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Recognitions:
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You could write the domain of x as [-2,∞)\{0,±1}
or as Dom(f) = {x |x [itex]\in[/itex] [-2,∞)\{0,±1}} Make sense? Notice the open parentheses on the infinity, since x cannot actually infinity (as it is not a number) |
| Jul30-08, 07:01 PM | #3 |
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OK, Nick. How should I express the domains of g and h?
Where g = [tex]\frac{1}{\sqrt{(2x^2 - 1)(x^2-1)}}[/tex] Would the domain of g be written as: dom(g)= R\{0, ±1} ? And... how would the domain of h be in this notation? |
| Jul30-08, 07:57 PM | #4 |
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Recognitions:
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Set Builder Notation
Yes that would be a way to write the domain of g.
For h you could write Dom(h) = [-2,∞)\{±1} |
| Jul30-08, 08:09 PM | #5 |
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Right
Thanks a lot! Makes sense now... |
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