Is the Antiderivative of 1/x Actually ln(x)?

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Homework Help Overview

The discussion revolves around the integration of the function 1 + 1/x + x over the interval [2, 8]. The original poster expresses uncertainty about the antiderivative of 1/x, questioning whether it is indeed ln(x).

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to integrate the function but is confused about the antiderivative of 1/x. Another participant suggests breaking the problem into separate integrals for clarity.

Discussion Status

The discussion includes attempts to clarify the integration process, with some participants providing guidance on separating the integrals. However, there is no explicit consensus on the original poster's concerns regarding the antiderivative of 1/x.

Contextual Notes

The original poster's confusion may stem from a misunderstanding of the notation or properties of logarithmic functions in integration.

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ive been trying to do this problem and its annoying!


The function to be integrated: 1 + 1/x + x dx


Interval: [8,2]

when anti differentiating the fuction i get x + x^2/2 + lnx but i don't think the integral of 1/x is lnx...help would be appreciated
 
Last edited:
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The function to be integrated: 1 + - + x dx
x

What does this mean? + - +?

cookiemonster
 
sorry updated on error
 
You can separate the problem into three little ones.

[tex]\int_2^8 \left( 1 + \frac{1}{x} + x \right) \,dx = \int_2^8 1 \, dx + \int_2^8 \frac{1}{x} \, dx + \int_2^8 x \, dx[/tex]

And

[tex]\int \frac{dx}{x} = \ln{|x|}[/tex]

cookiemonster
 
thanks a lot cookie. kudos goes out to you :smile:
 

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