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Fulcrum problem (I think)by ICLKennyg
Tags: fulcrum 
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#1
Aug1208, 09:08 PM

P: 2

I have a problem and it's been a while since I took a physics class.
So camera tripods are rated in weight... but this is more a function of torque than weight. The idea is the head can only hold so much force level. Obviously as the lens weight and length increases the force on the camera and tripod head gets worse. I am looking for a formula that will tell me what a lens will give me in a torque force on a tripod head. Sorry google doesn't seem to have much help on this. For simplicity's sake we can assume that the camera has no thickness. If a camera weighs 500g and a lens weighs 1kg distributed to a balancing point of 4cm away from the camera and 6cm away from the end (10cm long lens) how much torque would this generate on the tripod head. If it really matters the camera in question is 5cm wide with the mount roughly in the middle. Also in case it's important the distance from the tripod mount (bottom) to the center of the lens mount is 3cm. A quick diagram of what I am talking about. http://kj.stillabower.net/forum/imgs/camera.jpg 


#2
Aug1308, 09:16 AM

P: 72

The answer appears to be quite simple to figure though. If the cg (center of gravity) of the camera is exactly over the vertical shaft of the tripod, it will present 0 gram.centimeters torque to the head. If it is not, you must add (or subtract) the torque presented by the camera to that presented by the lens. Multiply the weight of the lens by the distance of its cg from the center of the tripod and you have the torque presented by the lens. Add that to the torque presented by the camera and you have the total torque. 


#3
Aug1308, 10:25 AM

P: 1,672

Anyway, like isly said just multiply the gravitational force of the lens and camera by the distance its offset from the hinge, assuming these vectors are orthonormal. If they are not, then just take the cross product. 


#4
Aug1308, 10:35 AM

P: 2

Fulcrum problem (I think)
http://kj.stillabower.net/forums/img/camera.jpg Do the units matter, or will they cancel as long as they are consistant? 


#5
Aug1308, 10:44 AM

P: 72

All this time I've thought torque to be: n. The moment of a force; the measure of a force's tendency to produce torsion and rotation about an axis, equal to the vector product of the radius vector from the axis of rotation to the point of application of the force and the force vector. A turning or twisting force The object being torqued does not have to be rotating. The torsional force, quantified in footpounds, gramcentimeters, kilogrammeters or some other understandable units is still properly labeled as torque. My understanding is that structural engineers use the term "moment" to describe a similar static force on beams, that force being calculated much the same as torque on a hex head bolt is calculated...except it's more complicated than using one distance and one force. 


#6
Aug1308, 10:47 AM

P: 72




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