
#1
Aug2208, 02:00 PM

P: 25

There's a problem in my textbook where it gives the emf of a battery, its internal resistance, and the net resistance of the circuit that it is connected to. Then it asks for the terminal voltage.
Actually, this is just a problem set (not exactly a textbook), so it doesn't teach me from previous examples. I'm still fumbling my way around these problems... Could someone please give me a hint on what to do? So far, from what I've read on the internet, you can calculate the terminal voltage as: V = emf  ir I have the emf, and the internal resistance...but no current is given. Haha, I'm so confused. 



#2
Aug2208, 02:04 PM

Emeritus
Sci Advisor
PF Gold
P: 10,424

You need to find the current through the total circuit, which is composed of both the external and internal resistances.
Next, you need to find the voltage drop across the internal resistance. You can use Ohm's law. Finally, you know how much voltage is being "lost" on the internal resistance, so you know what voltage will appear on the battery's terminals.  Warren 



#3
Aug2208, 02:15 PM

P: 25

Ok, so the battery's emf is 6V, internal resistance is 0.6 Ohms, and the circuit's net resistance is 7.20 Ohms. When you said: So, I have a current of 6.0/7.8 = 0.769 Amps ?? 6.0 V  0.462 V = 5.54 V, which is the answer. So...I don't need to worry about the resistance through the circuit? 



#4
Aug2208, 03:12 PM

P: 1,672

Terminal Voltage of a Battery
Not when you are only concerned about the voltage across the battery terminals, then the rest of the circuit is irrelevant. Remember voltage is the potential between two points, where current is a conserved flow.



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