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Distance/speed problemby wadesweatt
Tags: distance or speed 
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#1
Aug2308, 03:20 PM

P: 33

A horse canters away from its trainer in a straight line, moving 140 m away in 14.0 s. It then turns abruptly and gallops halfway back in 4.3 s.
(a) Calculate its average speed. (m/s) (b) Calculate its average velocity for the entire trip, using "away from the trainer" as the positive direction. (m/s) To start, I have drawn a graph to represent this situation, with time on the xaxis and distance on the yaxis. 1) I don't know how average speed and average velocity are different (since I thought they were both how fast something is going, or the slope of the graph), and 2) I don't know how to find the derivative of the graph since it is not linear and I am given no additional information about the equation of the graph. Maybe I am thinking way too far into this. I am new to physics, but I've had lots of math. Thanks in advance for the help. Wade 


#2
Aug2308, 03:52 PM

P: 79

Well if you know anything about vectors and scalars, then the difference should be easy to realize that speed is a scalar value and velocity is a vector value.
average speed = total distance covered / time average velocity = total displacement / time 


#3
Aug2308, 04:05 PM

P: 33

Thanks for the explanation. Yep, I've never had any college or high school physics before so I had never heard about that difference.



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