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a logical question.. |
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| Aug24-08, 11:07 AM | #1 |
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a logical question..
data:
every body who has a blue eyes has a short tail . every white bunny has a blue eyes. which one of this arguments when added to the data leads to the conclution "tom is not a rabbit" . A.the eyes of tom is blue and his tail is short. B.tom is white and he has a long tail. C.tom is black and his tail is short. D.tom has a green eyes and he has a long tail. what is the algorith for solving such a question. |
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| Aug25-08, 12:11 PM | #2 |
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Just use Venn diagrams and it will demonstrate B
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| Aug25-08, 03:22 PM | #3 |
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i drawed many circles representing each group
and subgroup i dont how to solve this kind of question usin Venn |
| Aug25-08, 07:22 PM | #4 |
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a logical question..
Venn diagrams probably won't help much here, because you've got 4 overlapping categories-- tail length, eye color, species, and color. With 3 overlapping characteristics or fewer, Venn diagrams are great. But when you get to 4, suddenly you can't stick with the traditional Venn "circles", and have to switch to bizarre other shapes. And with 5 categories, I don't even think it's possible to show all the conceivable overlaps.
For this problem, attack it just like every other logic problem. Try each suggestion, and see where it takes you: A.the eyes of tom is blue and his tail is short. Can Tom be a rabbit? Let's assume he is a rabbit, and see if we get any contradictions: We know that if he has blue eyes, then he has to have a short tail. Well, that's ok. We also know that every bunny that's white has blue eyes. And we don't even know what color Tom is in this situation. So no contradictions. B.tom is white and he has a long tail. Again, assume Tom is a rabbit. We know that if he has blue eyes (which we don't know in this case), he has to have a short tail. So, no problems yet. But next we know that every white bunny has blue eyes. And as it turns out, we know that Tom is a white bunny. Therefore, we know he *HAS* to have blue eyes! Acha! Well, with this new piece of information, we have to go back to the first rule and see if we have any brand new contradictions. Turns out we do. We now know Tom's eyes are blue, which means that he HAS to have a short tail. Unfortunately, Tom has a LONG tail. So this contradiction means that our assumption (that Tom was a rabbit) must be FALSE. Tom cannot be a rabbit. C.tom is black and his tail is short. Again, assume Tom is a rabbit. If he has blue eyes (nope!) then he has to have a short tail. No contradictions. And if he's a white bunny (nope! He's a black bunny), then he has to have blue eyes. Again, no contradictions. D.tom has a green eyes and he has a long tail. Ok, one last time, assuming Tom's a bunny. If he has blue eyes (again, no!) then he has to have a short tail. No problem. And we know if he's a white bunny (we don't know his color), then he has to have blue eyes. So he could be an orange bunny, and we'd have no problems. DaveE |
| Aug25-08, 09:30 PM | #5 |
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It worked fine for this example, for me at least ;) |
| Aug25-08, 09:59 PM | #6 |
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Again, it's not that you can't get it to work-- it's that I found it to be grossly unhelpful in this instance. By contrast, I probably spent about 2 minutes trying to draw Venn diagrams before saying "screw this", at which point I solved the problem in about 30 seconds or so just by following the logic as stated. I would, however, be curious to see how you arranged your diagram, assuming you used 4 circles to represent the 4 traits. All of my diagrams looked kind of patched together since I had little related-but-not-touching bubbles and/or non-circular shapes that I didn't like. DaveE |
| Aug26-08, 08:21 AM | #7 |
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Well, I feel silly. For whatever reason, I woke up this morning and figured out why my Venn diagrams were totally wrong. I had been drawing "white bunnies" as a distinct circle, rather than an intersection.
DaveE |
| Aug26-08, 08:34 AM | #8 |
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| Aug26-08, 01:56 PM | #9 |
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can you please pos your diagram
so ill learn how to implement it on other questions i need to solve this kind of questions in one minute unlike the previos stuff how do i solve it in a minute |
| Aug26-08, 05:20 PM | #10 |
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2. within the "everybody" circle, draw another circle. label it "short tail". therefore, everything outside this circle has a long tail. 3. within "short tail" circle draw a circle. Label it "blue eyes" 4. draw the last circle within "everybody" and partially intersecting the "blue eyes" circle, but not entirely within "short tail" Label this circle "bunnies". Further, label the intersection of "bunnies" and "blue eyes" as "white bunnies" By reading the choices and inspecting the diagram, you can see that since all white bunnies are contained within the blue eye circle, and the blue eye circle is completely contained within the short tail circle, that the only way Tom could be a rabbit and be white, is if he has a short tail, therefore, if he has a long tail per B, he can't be a rabbit and so the answer is B whew ! good luck on the minute time limit |
| Aug27-08, 05:23 AM | #11 |
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thanks
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| Aug27-08, 11:26 AM | #12 |
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As stated, though, with Venn diagrams, don't bother drawing it out if you've got a 1 minute time limit. Maybe if the same diagram is applicable for a bunch of related problems, but otherwise, it might be more time consuming than just going through things on your own... DaveE |
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